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mylen [45]
3 years ago
11

Several students at a university were surveyed about how they

Mathematics
2 answers:
NNADVOKAT [17]3 years ago
5 0

Answer:

Step-by-step explanation:

0.190

Anarel [89]3 years ago
4 0
Okay so the answer would be
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The perimeters of two similar triangles are 25 cm and 15 cm respectively. If one side of the first
Vanyuwa [196]

Answer:

5.4cm

Step-by-step explanation:

In similar triangles, the perimeter of the triangles will be in the ratio of their corresponding sides.

The ratio of their perimeter is  

perimeterofΔ2          15

---------------------   = -------------

perimeterofΔ1           25  

So, the side of triangle 2 will be  

  9  *  15                  15

----------------  =   --------------

​  sideofΔ2                25

=  

​⟹side of Δ2=           25  / 9∗15         =5.4.

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3 years ago
Free Póints for all ​
lyudmila [28]

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3 years ago
What is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)?
spayn [35]

Answer: 6,8 and 10

Step-by-step explanation:

To find the length , all we need to find is the distance between each point ,

the formula for calculating distance between two points is given by :

D = \sqrt{(x_{2}-x_{1}) ^{2}+(y_{2}-y_{1}) ^{2}}

Let the points be :

A ( -5,-1)

B(-5,5)

C(3,-1)

Calculating the length AB , we have

D1 = \sqrt{(x_{2}-x_{1}) ^{2}+(y_{2}-y_{1}) ^{2}}

D1 = \sqrt{(-5+5)^{2}+(5+1)^{2}}

D1 = \sqrt{36}

D1= 6

Calculating the length AC , we have

D2 = \sqrt{(x_{2}-x_{1}) ^{2}+(y_{2}-y_{1}) ^{2}}

D2 = \sqrt{(3+5)^{2}+(-1+1)^{2}}

D2 = \sqrt{64}

D2 = 8

Calculating the length BC , we have

D3 = \sqrt{(x_{2}-x_{1}) ^{2}+(y_{2}-y_{1}) ^{2}}

D3 = \sqrt{(3+5)^{2}+(-1-5)^{2}}

D3 = \sqrt{100}

D3 = 10

Therefore ,the length of the sides of the triangle are 6,8 and 10

3 0
3 years ago
Pleasee Help !!!!
lions [1.4K]
Hey dhsidvxhejfbeifbshdjdbd
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3 years ago
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