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professor190 [17]
3 years ago
11

Solve for x and y:

Mathematics
1 answer:
Oksanka [162]3 years ago
8 0

Answer:

O d. (7,5)

Step-by-step explanation:

x – 3y = -8 (1)

3x + 2y = 31 (2)

From (1)

x = -8 + 3y

Substitute x = -8 + 3y into (2)

3x + 2y = 31 (2)

3(-8 + 3y) + 2y = 31

-24 + 9y + 2y = 31

-24 + 11y = 31

11y = 31 + 24

11y = 55

y = 55/11

y = 5

Substitute y = 5 into (1)

x – 3y = -8 (1)

x - 3(5) = -8

x - 15 = -8

x = -8 + 15

x = 7

(x, y) = (7, 5)

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Please help me thank you and show all work
AleksAgata [21]
Proportional:
82.8 / 92 = 0.9
73.8 / 82 = 0.9
so
FG / 47 = 0.9
FG = 47 * 0.9
FG = 42.3

answer

The distance between 2 campsites is 42.3 m.



8 0
3 years ago
The coordinate plane below represents a city. Points A through F are schools in the city. graph of coordinate plane. Point A is
Ray Of Light [21]
Part A;
There are many system of inequalities that can be created such that only contain points A and E in the overlapping shaded regions.

Any system of inequalities which is satisfied by (2, -3) and (3, 1) but is not satisfied by (-3, -4), (-4, 2), (2, 4) and (-2, 3) can serve.

An example of such system of equation is
y ≤ x
y ≥ -2x
The system of equation above represent all the points in the first quadrant of the coordinate system.
The area above the line y = -2x and to the right of the line y = x is shaded.



Part B:
It can be verified that points A and E are solutions to the system of inequalities above by substituting the coordinates of points A and E into the system of equations and see whether they are true.

Substituting A(2, -3) into the system we have:
-3 ≤ 2
-3 ≥ -2(2) ⇒ -3 ≥ -4
as can be seen the two inequalities above are true, hence point A is a solution to the set of inequalities.

Also, substituting E(3, 1) into the system we have:
1 ≤ 3
1 ≥ -2(3) ⇒ 1 ≥ -6
as can be seen the two inequalities above are true, hence point E is a solution to the set of inequalities.



Part C:
Given that William can only attend a school in her designated zone and that William's zone is defined by y < −x - 1.

To identify the schools that William is allowed to attend, we substitute the coordinates of the points A to F into the inequality defining William's zone.

For point A(2, -3): -3 < -(2) - 1 ⇒ -3 < -2 - 1 ⇒ -3 < -3 which is false

For point B(-3, -4): -4 < -(-3) - 1 ⇒ -4 < 3 - 1 ⇒ -4 < 2 which is true

For point C(-4, 2): 2 < -(-4) - 1 ⇒ 2 < 4 - 1 ⇒ 2 < 3 which is true

For point D(2, 4): 4 < -(2) - 1 ⇒ 4 < -2 - 1 ⇒ 4 < -3 which is false

For point E(3, 1): 1 < -(3) - 1 ⇒ 1 < -3 - 1 ⇒ 1 < -4 which is false

For point F(-2, 3): 3 < -(-2) - 1 ⇒ 3 < 2 - 1 ⇒ 3 < 1 which is false

Therefore, the schools that Natalie is allowed to attend are the schools at point B and C.
4 0
3 years ago
Help help help help help help
muminat

Answer:

t= - 48

Step-by-step explanation:

t/8 - 6= -12 add 6 to both side

t/8= -6 multiple by 8

t= -48

3 0
3 years ago
Read 2 more answers
If a rectangle has an area of 2x^2+7x+3 find the perimeter
Helen [10]

Answer:

Perimeter of the rectangle=6x+8 square units

Step-by-step explanation:

Given that area of rectangle is 2x^2+7x+3

Area of rectangle=lw square units

2x^2+7x+3=2x^2+x+6x+3

=x(2x+1)+3(2x+1)

=(x+3)(2x+1)

2x^2+7x+3=(x+3)(2x+1)

Comparing the above equation with the given area we get

lw=(x+3)(2x+1)

Therefore length=x+3 and width=2x+1

To find the perimeter :

Perimeter of the rectangle=2(l+w) square units

=2((x+3)+(2x+1))

=2(x+3+2x+1)

=2(3x+4)

=6x+8

Therefore perimeter of the rectangle=6x+8 square units

6 0
4 years ago
What does a slope tell us
8_murik_8 [283]
It go vroom! vroom vroom vroom
7 0
3 years ago
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