Question

If a rectangle has an area of 2x^2+7x+3 find the perimeter

Answer 1

Answer:

Perimeter of the rectangle=6x+8 square units

Step-by-step explanation:

Given that area of rectangle is $2x^2+7x+3$

Area of rectangle=lw square units

$2x^2+7x+3=2x^2+x+6x+3$

$=x(2x+1)+3(2x+1)$

$=(x+3)(2x+1)$

$2x^2+7x+3=(x+3)(2x+1)$

Comparing the above equation with the given area we get

lw=(x+3)(2x+1)

Therefore length=x+3 and width=2x+1

To find the perimeter :

Perimeter of the rectangle=2(l+w) square units

$=2((x+3)+(2x+1))$

$=2(x+3+2x+1)$

$=2(3x+4)$

$=6x+8$

Therefore perimeter of the rectangle=6x+8 square units