Answer:
1. y = -10x + 6
2. y = -x - 6
3. y = 13x + 110
4. y = -5x + 47
5. y = 7/4 x -7
Step-by-step explanation:
2. m = - 1 and Y-intercept: -20 - (- 1)(14) = -6
3. m = 13 and Y-intercept: -7 - (13)(- 9) = 110
4. (10,-3) and (7,12)
Slope = (12 - - 3)(7- 10) = 15/-3 = -5
y- intercept = 12 - (-5)(7) = 47
5. (4,0) and (0, -7)
Slope: (-7-0)/(0-4) = -7/-4 = 7/4
y-intercept: -7 - 7/4)(0) = -7
The space between the two spheres will be the volume of the larger sphere minus the volume of the smaller sphere. Given that the volume of any sphere is:
V=(4πr^3)/3 The space between to sphere of different radius and positioned about the same center is:
S=(4πR^3)/3-(4πr^3)/3 I used S=volume of space, R=larger radius and r=smaller radius...
S=(4π/3)(R^3-r^3), we are told that R=5 and r=4 so
S=(4π/3)(5^3-4^3)
S=(4π/3)(125-64)
S=(4π/3)(61)
S=244π/61
S=4π cm^3
S≈12.57 cm^3 (to nearest hundredth of a ml)
Answer: 325
Explanation:
Let the number of adult tickets be <em>x </em>
( since there are an unknown amount of tickets for adults, we already know how many student tickets there are)
Let the number of student tickets be <em>x+</em>60
710=<em>x+x</em>+60
710=2x+60
-60 -60
650=2x
650/2
= 325
Adult tickets=325
Student tickets=385
Answer: -4
Step-by-step explanation:
Consider one pyramid
Side length of base = 1.5cm and its height is 1 cm
Slant height of one of the lateral faces = sqrt(1^2 + 0.75^2) = 1.25 cm
Area of one of the triangular faces = 0.5 * 1.5* 1.25 = 0.9375 cm^2
There are 8 of these so the required surface area = 8 * 0.9375
= 7.5 cm^2 Answer
