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seropon [69]
3 years ago
6

I WILLL GIVE THE BRAINLEST!!!!

Mathematics
2 answers:
mezya [45]3 years ago
8 0
C= 2π*r = 2*3.14*4 = 25.12
C= 25.12
DedPeter [7]3 years ago
4 0

Answer:

25.13

Step-by-step explanation:

C=2πr=2·π·4≈25.13274cm

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Mr. Sánchez owns a square field. The side lengths are 0.9 kilometers. There are 1,980 prairie dog burrows in the fields. What is
Simora [160]
The first thing we are going to do is find the area of the field. To do this we are going to use the area of a square formula: A=s^2
Were 
A is the area in square kilometers 
s is one of the sides of the square
We know for our problem that  the side lengths of the field are 0.9 kilometers, so s=0.9. Lets replace that value in our formula to find A:
A=(0.9)^2
A=0.81 

Now, to find the population density of the filed, we are going to use the population density formula: P_{d}= \frac{I}{A}
where
P_{d} is the population density in <span>in burrows per square kilometer
</span>I is the number of burrows 
A is the are of the field
We know that I=1980 and A=0.81, so lets replace those values in our formula:
P_{d}= \frac{1980}{0.81}
P_{d}=2444.4

We can conclude that the <span>density of prairie dog burrows is approximately 2444 burrws per square kilometer.</span>
5 0
2 years ago
Two canoes travel down a river, starting at 9:00 a.M. One canoe travels twice as fast as the other. After 4.5 hours, the canoes
Vedmedyk [2.9K]

Answer:

v_1=3.33 \ miles/hour\\v_2=6.66 \ miles/hour

Step-by-step explanation:

<u>Constant Speed Motion </u>

When the object travels the same distances in the same period of time, the speed is constant and is can be calculated as

\displaystyle v=\frac{x}{t}

where x is the distance and t is the time

There are two canoes traveling at speeds v1 and v2. One of them has twice the speed as the other. Let's say

v_2=2v_1

When t hours have passed, the canoes have traveled x1 and x2 respectively.

x_1=v_1t

x_2=v_2t

Since

v_2=2v_1

Then

x_2=2v_1t

The distance between them is

X=x_2-x_1=2v_1t-v_1t

X=v_1t

That distance is known and equals 11.25 miles, thus

v_1t=15

Solving for v1 and using t=4.5 hours

\displaystyle v_1=\frac{15}{4.5}

v_1=3.33 \ miles/hour

v_2=2\times 3.33

\boxed{v_2=6.66 \ miles/hour}

6 0
2 years ago
Two boxers bump heads in a boxing match. The referee will check for a concussion on one of the boxers. Consider a null hypothesi
Natalka [10]
B,hope this helped!
4 0
2 years ago
Use partial products to multiply 2,104 x 8. 2,104 32 8 x 4 ones 0 8 x 0 tens N 1 hundreds 8 x 2 thousands - 16.000​
xeze [42]

9514 1404 393

Answer:

  16832

Step-by-step explanation:

As your problem statement says, ...

  2104 × 8 = 4×8 +00×8 +100×8 +2000×8

  = 32 +0 +800 +16000

  = 16,832

7 0
3 years ago
Write the equation of the line passing through the points (-4,-1) and (2,8)
klio [65]
<h3><u>Explanation</u><u>:</u></h3>
  • Calculate the slope with two given coordinate points by using rise over run.

m =  \frac{y_2 - y_1}{x_2 - x_1}

Let these points

\begin{cases}(x_1, y_1) = ( - 4,  - 1) \\ (x_2, y_2) = ( 2,  8) \end{cases}

m =  \frac{8 - ( - 1)}{2 - ( - 4)}  \\ m =  \frac{8 + 1}{2 + 4}  \Longrightarrow \frac{9}{6}  \Longrightarrow \frac{3}{2}  \\ m =  \frac{3}{2}

  • Slope-Intercept

y = mx + b \\ m = slope \\ b = y - intercept

Substitute the value of m in the equation.

y =  \frac{3}{2} x + b

  • Substitute any coordinate points that are given or part of the graph in the equation.

(x_, y) = ( - 4,  - 1)

- 1 =  \frac{3}{2} ( - 4) + b

  • Solve the equation for b-term.

- 1 =  \frac{3}{ \cancel{2}} ( \cancel{ - 4})   + b\\  - 1 = 3( - 2) + b \\  - 1 =  - 6 + b \\  - 1 + 6 = b \\ 5 = b

  • Rewrite the equation by substituting the value of b in the equation.

y =  \frac{3}{2} x + 5

<h3><u>Answer</u></h3>

\large \boxed{y =  \frac{3}{2} x + 5}

<em>If</em><em> </em><em>you</em><em> </em><em>have</em><em> </em><em>any</em><em> </em><em>questions</em><em> </em><em>related</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>answer</em><em>,</em><em> </em><em>feel</em><em> </em><em>free</em><em> </em><em>to</em><em> </em><em>ask</em><em> </em><em>via</em><em> </em><em>comment</em><em>.</em>

7 0
2 years ago
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