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3 years ago

How to find perpendicular slope to a line?

Mathematics

2 answers:

Wittaler [7]3 years ago

4 0

Answer:

Find the first point that the point are touching a line and then go to the next and see the difference

Step-by-step explanation:

oee [108]3 years ago

4 0

Answer:

flip your slope if its positive already make it negative if its negative make it positive

Step-by-step explanation:

for example say your slope is -4 you flip it and it becomes 1/4

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A worker drags a box of mass 50 kg across a horizontal floor. The worker attaches a rope to the box and pulls on the rope so tha

Arlecino [84]

Answer:

A) $F=\displaystyle{\frac{m(a+ \mu g)}{\cos(\alpha) -\mu \sin(\alpha)} }$ with $a = \frac{2\Delta x}{t^2}$

B) The magnitude of the pulling force is 24 % of the magnitude of the gravitational force acting on the box

Step-by-step explanation:

A) The forces acting on the box are the pulling force that the worker exerts on the rope, the friction, the normal force, and the gravitational force. See the attached diagram. Since the pulling force on the rope makes an angle with the horizontal, this will have components in the x and y-axis (see diagram).

In the y-axis, the box does not move, therefore:

$\sum_{y} F = 0\\F\sin(\alpha) + N - F_g = 0\\N = F_g - F\sin(\alpha)\\N = mg - F\sin(\alpha)$ (1)

where $\alpha$ is the given angle of the rope with the horizontal.

In the x-axis, the box moves with an acceleration $a$ that can be calculated as a function of the given displacement and time interval as:

$a = \frac{2\Delta x}{t^2}$ and the force equation is:

$\sum_{x} F = ma\\F\cos(\alpha) -f =ma\\F\cos(\alpha) - \mu N = ma$

now substituting $N$ from equation (1):

$F\cos(\alpha) - \mu N = ma\\F\cos(\alpha) - \mu (mg - F\sin(\alpha))=ma\\F\cos(\alpha) - \mu mg -\mu F\sin(\alpha)=ma\\F\cos(\alpha) -\mu F\sin(\alpha)=ma+ \mu mg\\F(\cos(\alpha) -\mu \sin(\alpha))=ma+ \mu mg\\\boxed{F=\frac{m(a+ \mu g)}{\cos(\alpha) -\mu \sin(\alpha)}}$

and putting the expression for the acceleration:

$\boxed{F=\frac{m \frac{2\Delta x}{t^2}+ \mu mg}{\cos(\alpha) -\mu \sin(\alpha)}}$ (2)

which is the requested expression

B) Substituting the values in (2) and using $g=9.8\ \rm{ms^{-2}}$ :

$F=\frac{50 \cdot ( 0.762939+ 0.1\cdot \cdot 9.8)}{\cos(36.8^{\circ}) -0.1 \sin(36.8^{\circ})}\\F=\frac{87.147}{0.740829} \\F=11.634\ \rm{N}$

The gravitational force acting on the box is:

$F_g=mg=50\cdot9.8=490\ \rm{N}$

$F/F_g = (117.634/490)\cdot 100 = 24 \%$

Thus, the magnitude of the pulling force is 24 % of the magnitude of the gravitational force acting on the box.

8 0

4 years ago

Unit Test / 16 of 25

Rzqust [24]

Answer:

Step-by-step explanation:

For the minimum free throws, he must put every throw to the basket.

So, let n be the number of throws for Tuesday, in which all the throws are successful.

So, over both the days, total free throws he makes= 15+n.

Total numbers of throws that went in the basket= 6+n.

As he wants at least 80% of his balls to go in the basket.

So, 6+n is greater than or equal to 809% of 15+n, i.e

$6+n\geq \frac{80}{100}\times (15+n)$

$\Rightarrow 30+5n\geq 60+4n$

$\Rightarrow n\geq 30.$

Hence, the minimum number of free throws required on Tuesday to reach his goal is 30.

7 0

3 years ago

There are 92 students in a chemistry class. The instructor must choose two students at random. Students in a Chemistry Class Aca

Sergio039 [100]

Answer:

0.0108 = 1.08% probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Probability that a sophomore non-Chemistry major

Out of 92 students, 9 are non-chemistry major sophomores. So

$P(A) = \frac{9}{92}$

Then a junior non-Chemistry major are chosen at random.

Now, there are 91 students(1 has been chosen), of which 10 are non-chemistry major juniors. So

$P(B) = \frac{10}{91}$

What is the probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random

$P = P(A)*P(B) = \frac{9}{92}*\frac{10}{91} = \frac{9*10}{92*91} = 0.0108$

0.0108 = 1.08% probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random.

8 0

3 years ago

Can anyone help me with this problem?

Paraphin [41]

Answer:

(12, 0)

Step-by-step explanation:

The T4-5 means translate 4 units to the right and 5 units down.

So 8 + 4 = 12

5 - 5 = 0

The final answer is (12, 0)

Hope it helped!

4 0

3 years ago

The graph of y=f(x) is shown on the grid.<br> Use the graph to workout and estimate for f(2.5)

Wewaii [24]

Check the picture below.

6 0

2 years ago

How to find perpendicular slope to a line?​

How to find perpendicular slope to a line?