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kipiarov [429]
3 years ago
12

Find the surface area of that part of the plane 9x 5y z=5 that lies inside the elliptic cylinder x216 y281=1

Mathematics
1 answer:
Yakvenalex [24]3 years ago
3 0
I assume the equation of the plane is 9x+5y+z=5 and the cylinder has equation \dfrac{x^2}{16}+\dfrac{y^2}{81}=1.

I don't know what techniques are available to you, so I'll resort to (in my opinion) the most reliable: surface integration.

The surface of intersection S is an ellipse in three dimensional space which can be parameterized by \mathbf x(u,v)=\langle 4u\cos v,9u\sin v,5-36u\cos v-45 u\sin v\rangle, with u\in[0,1] and v\in[0,2\pi].

The area is then given by the integral
\displaystyle\iint_S\mathrm dA=\int_0^1\int_0^{2\pi}\left\|\dfrac{\partial\mathbf x}{\partial u}\times\dfrac{\partial\mathbf x}{\partial v}\right\|\,\mathrm dv\,\mathrm du=36\sqrt{107}\pi
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