R

12-5
r

7 -> That's true once 7+5

12 = 12

12
or
7/9<0 That's not true once 7/9>0
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EZ!
Let's say each box costs $X and each program costs $Y
Thus, Mike's family spent:
$(5X+3Y)
or
$41
Sean's family spent
$(3X+2Y)
or
$26
This yields us a system of two equations:
5x+3y=41
3x+2y=26
<span>5x+3y=41
</span>2y=26-3x
<span>5x+3y=41
</span><span>y=13-1.5x
</span>
5x+3(13-1.5x)=41
y=13-1.5x
5x+39-4.5x=41
<span>y=13-1.5x
</span>
0.5x+39=41
<span>y=13-1.5x
</span>
0.5x=2
<span>y=13-1.5x
</span>
x=4
<span>y=13-1.5x
</span>
x=4
<span>y=7
</span>
Each box costs $4 and each program costs $7
100 - 20 = 80
80 / 8 = 10
There are 10 multiples of 8 between 20 and 100