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aivan3 [116]
3 years ago
13

Calculate trend values by method of least squares

Mathematics
1 answer:
Grace [21]3 years ago
5 0

Answer:

It is a mathematical method and with it gives a fitted trend line for the set of data in such a manner that the following tow conditions are satisfied. The sum of the deviation of the actual values of Y and the computed values of Y is zero.

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Find the area of the circle.
S_A_V [24]

Answer:

The area of the circle is A = 12.56 m²

Step-by-step explanation:

* Lets explain how to solve the problem

- The area of any circle is A = π r² , where r is the radius of the circle

- In any circle the length of the radius is half the length of its diameter

* Lets solve the problem

- The diameter of the circle is 4 meters

∵ The radius of the circle = 1/2 diameter

∵ The diameter = 4 meters

∴ The radius = 1/2 × 4 = 2 meters

- The area of the circle is A = π r²

∵ The value of π = 3.14

∵ The length of r = 2 meters

- Substitute the value of r in the rule of the area

∵ A = π r²

∴ A = 3.14 × (2)²

∴ A = 3.14 × 4 = 12.56 meters²

* The area of the circle is A = 12.56 m²

6 0
3 years ago
NEED HELP WITH IXL S.16​
zimovet [89]

Answer:

The slope of Function A is less than the slope of Function B.

Step-by-step explanation:

To know that Function A has a smaller slope than Function B we need to find out the slope of function A and B.

Function A is y = x + 1. I would graph it on the desmos calculator and the line should pop up. Seeing the line is square points, the line can now identify with a slope of 1.

Function B I would do the equation y2-y1/x2-x1 and I got 1-17/-1-3 which is equal to 4. Now we know that the slope of B is 4.

So B is equal to 4 and A is equal to 1 meaning the second option is correct.

I hope this helps:)

3 0
3 years ago
What is the area of a triangle with a base of 4v^3 and a height of vu^2?
IgorLugansk [536]
Answer:  The area of the triangle is:     " 2v⁴u² square units" ;
                                            or, write as:  " 2v⁴u² units² " .
______________________________________________________
<u>Note</u>:  The formula/equation for the area, "A", of a triangle is:

             A = (1/2) * b * h  ;   or:  A = (b * h) / 2 ; 
______________________________________________________
  in which:   "A" = "area" ; 
                   "b" = "base length" ;
                   "h" = "[perpendicular] height" ; 
______________________________________________________
We are asked to solve for the area, "A" .

We are given:  "b = 4v³ " ;  "h = vu² " ;

So;  to find the area, "A", of the triangle, we plug these given values into the formula; and solve/ simplify:
____________________________________________________
     A = (1/2) * b * h ; 

     A = (1/2) * (4v³) * (vu²) ; 

     A = 2v³ * vu² ;

     A = 2v⁴u²  square units.

Answer:  The area of the triangle is:     " 2v⁴u² square units" ;
                                            or, write as:  " 2v⁴u² units² " .
 ___________________________________________________
3 0
3 years ago
F(x)=((×))<br><img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%7B%7Bx%7D%7D" id="TexFormula1" title="f(x) = {{x}}" alt="f(x)
ira [324]
Let y = f(x),
y = x
For every unit that y increases, x increases by 1 unit. The straight line graph will cut the y-axis at the origin (x = 0 & y = 0), and form 45° with both x-axis and y-axis at the original.

Hope this helps!
3 0
3 years ago
How do I Factor 9x^6 - 16y^6
Viefleur [7K]
(3x^3+4y^3)(3y^3-4y^3)
3 0
4 years ago
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