Ask question

Ask question

All categories

2 years ago

14

Which of the following is a direct negative consequence of aquaculture?

1 answer:

seraphim [82]2 years ago

5 0

D) relieving fishing pressure on over fished species

You might be interested in

Which statements accurate describe tropical rain forest

Dmitry_Shevchenko [17]

what are the statements?

3 0

2 years ago

Read 2 more answers

What dose a scientist do if a hypothesis is supported?what dose he or she do is not supported

Alekssandra [29.7K]

If a hypothesis is supported it becomes a theory if its not he or she has to make another hypothesis

5 0

3 years ago

Read 2 more answers

How did the Earth get these different layers? Did the Earth always have very separate, distinct layers? Describe what happened.

Orlov [11]

Answer: The different layers are a result of lighter parts (such as the continental crust) settling at the surface level and heavier parts (such as iron and nickel in the core) settling in the middle. The layers separate by density, otherwise known as compositional layering. The earth did not always have these layers, as it had to undergo cooling to form some of them (like the continental crust).

7 0

2 years ago

In a hardy-weinberg population with two alleles, a and a, that are in equilibrium, the frequency of the allele a is 0. 3. What i

zavuch27 [327]

Here, given-

homozygous alleles 'a' have a frequency of 0.3.

Also the alleles are in equilibrium in a Hardy-Weinberg population. The frequency of individuals that are homozygous for this allele are= 0.49.

The Hardy-Weinberg equilibrium can be defined as the principle which states that the variation in the genetic makeup of a population remains constant and unchanged till there are no external interferences, influencing the population.

Calculation-

$p + q = 1\\0.3 + q= 1\\q= 1- 0.3\\\\q= 0.7$

Then to find the frequency of the individuals homozygous for this allele the following formula needs to be used-

$p^{2} + 2pq + q^{2} =1$

$p^{2} = dominant homozygous frequency\\2pq= heterozygous frequency\\q^{2} = recessive homozygous frequency\\$

Thus, the individuals homozygous for the allele can be calculated by $q^{2} = (0.7)^{2} \\= 0.49$

Learn more about the Hardy-Weinberg equilibrium here-

brainly.com/question/16823644

#SPJ4

4 0

1 year ago

Which statements about the regulation of transcription initiation in these genes are true?

katovenus [111]

The answer is 7......

8 0

2 years ago