Answer:
The turns of a graph is represented by the number of maximum or minimum that the function has.
If we differenciate f(x) we get:
f'(x)=4x^3+6x
f'(x)=2x(2x^2 + 3)
Therefore f'(x) =0, when x=0. Given that negative roots are not defined.
Therefore, the number of turns will be given by the number of solutions of f'(x) which is 1.
Attached you find the graph of the function which confirms the number of turns.
If the function had other solutions, the maximum number of turns it could have is 3! because f'(x) is a third degree polynomial, therefore it can't have more than 3 solutions!
Answer:
A(t) = 200+15t(1+0.02)^{t}
Step-by-step explanation:
Since the interest is calculated on the new balance every year.
Hence the formula used for compound interest is:
A = P(1+^{nt}
where, A =Amount after t years
P =Principal amount
200 is the initial balance and Since, here the $15 is added to the balance each year. Therefore, P = 200+15t
r = rate each year (0.02)
t = time (in years) (t)
n = no. of times the interest is compounded in a year (n=1)
Therefore, the recursive formula is:
A(t) = 200+15t(1+0.02)^{t}
Answer:
where is the problem
Step-by-step explanation:
Answer:
We have the next relation:
A = (b*d)/c
because we have direct variation with b and d, but inversely variation with c.
Now, if we have 3d instead of d, we have:
A' = (b*(3d))/c
now, we want A' = A. If b,c, and d are the same in both equations, we have that:
3bd/c = b*d/c
this will only be true if b or/and d are equal to 0.
If d remains unchanged, and we can play with the other two variables we have:
3b'd/c' = bd/c
3b'/c' = b/c
from this we can took that: if c' = c, then b' = b/3, and if b = b', then c' = 3c.
Of course, there are other infinitely large possible combinations that are also a solution for this problem where neither b' = b or c' = c
Answer:
135 degrees
Step-by-step explanation:
(8x-7)+(12x+57)=180
combine like terms
20x+50 = 180
subtract 50 on both sides
20x = 130
divide by 20
x = 130/20
x = 13/2
x = 6.5
cpq = 12x+57
cpq = 78 + 57
cpq = 135