11. 2x+3x+1=21
5x+1 =21
5x=20
x=4
TU= 2(4) which is 8
UB= 3(4)+1 which is 13
12. 4x-1 +2x-1=5x
6x-2=5x
-2=-1x
2=x
X=2
TU= 7
UB= 3
TB=10
Problem 13:
2x-8=x+17
2x=x+25
x=25
AB =42
BC=42
AC=84
Problem 14:
3x-31
-x+6
=
2x-37 for BC part now we solve for x
x+6=2x-37
6=x-37
43=x
So :
X=43
AB=49
AC=98
BC=49
To solve this question, we use simple division:
So, there are
10 servings of 4/5 of a cup in 8 cups.
Answer:
$1,562.50
Step-by-step explanation:
Markup= (selling price- cost)/cost
Let cost be represented by C
0.20 = (1875-C)/ C
0.20C = 1875 - C
0.20C+ C = 1875
1.20C=1875
Divide both sides by 1.20;
C= 1875/1.20
C= $1,562.50
The wholesale cost was $1,562.50
If x=-6 then y=54.
If x=-4 then y=51.
If x=-2 then y=48.
If x=0 then y=45.
If x=2 then y=42.
If x=4 then y=39.
If x=6 then y=36.
There are an infinite variety of pairs of numbers for 'x' and 'y'
that can make that equation true.
You can use that equation to draw a line on a graph. Then
EVERY point on the line is a solution to the equation.
'x' and 'y' don't have single values unless you have TWO equations.
True , is the answer ! :)
