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lutik1710 [3]
3 years ago
13

The reciprocal of 6 4/5 is

Mathematics
2 answers:
Bumek [7]3 years ago
5 0
To get the reciprocal of a number you divide 1 by that number. therefore the answer to this question is.14705882 or 34/5
kondor19780726 [428]3 years ago
3 0
It should be 34/5*. If you create an improper fraction out of the original one, then creating the reciprocal will be easier.
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VERY URGENT HAVE A TEST TO TAKE
Daniel [21]
The easiest way is to try the point (-4,1), that is, x=-4, y=1,
to see which equation works.
b works.

The usual way to do it is to find the equation of the circle
standard form of a circle is (x-h)²+(y-k)²=r², (h,k) are the coordinates of the center, r is the radius. 
in this case, the center is (-2,1), so (x+2)²+(y-1)²=r²
the given point (-4,1) is for you to find r: (-4+2)²+(1-1)²=r², r=2
so the equation is (x+2)²+(y-1)²=2² 
expand it: x²+4x+4+y²-2y+1=4
x²+y²+4x-2y+1=0, which is answer b.

5 0
3 years ago
Can someone please help me with this
schepotkina [342]

Answer:

y=25

2 of the y's = 50 in total

Step-by-step explanation:

180-115=x

x=65

180-90-65=y

y=25

5 0
2 years ago
What is the local minimum value of the function? (Round answer to the nearest hundredth) g(x)=x^4-5x^2+4
Serhud [2]
The local minimum of function is an argument x for which the first derivative of function g(x) is equal to zero, so:
g'(x)=0
g'(x)=(x^4-5x^2+4)'=4x^3-10x=0
x(4x^2-10)=0
x=0 or 4x^2-10=0
4x^2-10=0 /4
x^2-10/4=0
x^2-5/2=0
[x-sqrt(5/2)][x+sqrt(5/2)]=0

Now we have to check wchich argument gives the minimum value from x=0, x=sqrt(5/2) and x=-sqrt(5/2).
g(0)=4
g(sqrt(5/2))=25/4-5*5/2+4=4-25/4=-9/4
g(-sqrt(5/2))=-9/4
The answer is sqrt(5/2) and -sqrt(5/2).

4 0
3 years ago
Read 2 more answers
On Monday, David woke up at 7:25 A.M. and went to sleep at 8:30 P.M. How long was David awake?
kaheart [24]
13h and 5min. Hope this helps:)

6 0
3 years ago
Combining like terms with negative coefficients
den301095 [7]

Answer:

you add them, but keep the sign

Step-by-step explanation:

8 0
3 years ago
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