Question

Help please asap just the answers​

Answer 1

$\sf \bf {\boxed {\mathbb {GIVEN:}}}$

$a\:=\:2$, $b\:=\:-1$ and $c\:=\:-3$

7) $3 {a}^{2} - b$

Plugging in the values of $a$ and $b$, we have

$= 3( {2})^{2} - ( - 1)$

$= 3(2 \times 2) + 1$

$= 3 \times 4 + 1$

$= 12 + 1$

$= 13$

Hence, $\boxed{ c. \:13 }$ is the correct option.

8) ${a}^{3} {b}^{3} - abc$

Plugging in the values of $a$ and $b$ and $c$, we have

$= ({2})^{3} ( { - 1})^{3} - 2( - 1)( - 3)$

$= (2 \times 2 \times 2)( - 1 \times - 1 \times - 1) - 2(3)$

$= (8)( - 1) - 6$

$= - 8 - 6$

$= - 14$

Hence, $\boxed{ d.\:-14 }$ is the correct option.

$\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}$

Answer 2

$\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }$

$\huge\underline{\sf{\red{Problem:}}}$

7.) Detemine the value of $\sf{ {3a}^{2} -b.}$

$\huge\underline{\sf{\red{Given:}}}$

$\quad\quad\quad\quad\sf{a = 2}$

$\quad\quad\quad\quad\sf{b = - 1}$

$\quad\quad\quad\quad\sf{c = - 3}$

$\huge\underline{\sf{\red{Solution:}}}$

$\quad\quad\quad\quad\sf{⟶{3a}^{2} - b}$

$\quad \quad \quad \quad \sf{⟶{(3)( 2)}^{2} -( - 1)}$

$\quad \quad \quad \quad \sf{⟶3(4)-( - 1)}$

$\quad \quad \quad \quad \sf{⟶12-( - 1)}$

$\quad \quad \quad \quad \sf{⟶12 + 1 }$

$\quad \quad \quad \quad ⟶ \boxed{ \sf{ 13}}$

$\huge\underline{\sf{\red{Answer:}}}$

$\huge\quad \quad \underline{ \boxed{ \sf{ \red{7.)\:13}}}}$

8.) Find the value of $\sf{ {a}^{3} {b}^{3} - abc.}$

$\huge\underline{\sf{\red{Solution:}}}$

$\quad\quad\quad\quad\sf{⟶ {a}^{3} {b}^{3} - abc}$

$\quad\quad\quad\quad\sf{⟶{(2)}^{3} {( - 1)}^{3} - (2)( - 1)( - 3)}$

$\quad\quad\quad\quad\sf{⟶{(8)}{( - 1)} - ( - 2)( - 3)}$

$\quad\quad\quad\quad\sf{⟶{( - 8)} - ( 6)}$

$\quad\quad\quad\quad ⟶\boxed{\sf{ - 14}}$

$\huge\underline{\sf{\red{Answer:}}}$

$\huge\quad \quad \underline{ \boxed{ \sf{ \red{8.)-14}}}}$

$\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }$

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$\sf{\red{✍︎ C.Rose❀}}$