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olga nikolaevna [1]
3 years ago
15

Can you give the answers to these problems I let the pictures here (they are only two)

Mathematics
1 answer:
velikii [3]3 years ago
7 0

Answer:

Here's what I got

Step-by-step explanation:

(6n^2 - 6n - 5)(7n^2 + 6n - 5)

42n^4 - 6n^3 - 101n^2 + 25

(n^2 + 6n - 4)(2n - 4)

2n^3 + 8n^2 - 32n + 16

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How do you write -5.16 as a fraction
dmitriy555 [2]

Answer:

You could write -5.16 as -5 4/25

3 0
4 years ago
Read 2 more answers
Line L has equation 2x - 3y = 5. Line M passes through the point (2, -10) and is perpendicular to line L. Determine the equation
Whitepunk [10]
C has to be the right one
5 0
4 years ago
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<img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7Bm%7D%20%20%3D%20n%20" id="TexFormula1" title=" {2}^{m} = n " alt=" {2}^{m} =
sveta [45]

Answer:

\displaystyle n^3-\frac{1}{n^{2}}

Step-by-step explanation:

<u>Exponents Properties</u>

We need to recall the following properties of exponents:

(a^x)^y=(a^y)^x=a^{xy}

\displaystyle a^{-x}=\frac{1}{a^x}

We are given the expression:

2^m=n

We need to express the following expression in terms of n.

8^m-4^{-m}

It's necessary to modify the expression to use the given equivalence.

Recall 8=2^3 \text{ and }4 = 2^2. Thus:

(2^3)^m-(2^2)^{-m}

Applying the property:

(2^m)^3-(2^m)^{-2}

Substituting the given expression:

n^3-n^{-2}

Or, equivalently:

\mathbf{\displaystyle 8^m-4^{-m}= n^3-\frac{1}{n^{2}}}

5 0
3 years ago
How do I find the Derivative of a Function where the x is a number?
lisov135 [29]

Given a function <em>g(x)</em>, its derivative, if it exists, is equal to the limit

g'(x) = \displaystyle\lim_{h\to0}\frac{g(x+h)-g(x)}h

The limit is some expression that is itself a function of <em>x</em>. Then the derivative of <em>g(x)</em> at <em>x</em> = 1 is obtained by just plugging <em>x</em> = 1. In other words, find <em>g'(x)</em> - and this can be done with or without taking a limit - then evaluate <em>g'</em> (1).

Alternatively, you can directly find the derivative at a point by computing the limit

g'(1) = \displaystyle\lim_{h\to0}\frac{g(1+h)-g(1)}h

But this is essentially the same as the first method, we're just replacing <em>x</em> with 1.

Yet another way is to compute the limit

g'(1) = \displaystyle\lim_{x\to1}\frac{g(x)-g(1)}{x-1}

but this is really the same limit with <em>h</em> = <em>x</em> - 1.

You do not compute <em>g</em> (1) first, because as you say, that's just a constant, so its derivative is zero. But you're not concerned with the derivative of some <em>number</em>, you care about the derivative of a function that depends on a <em>variable.</em>

8 0
3 years ago
The circumference of a circle is 47.1 and the diameter of the circle is 15. Which best represents the value of π? 47.1/15 7.54/7
Vlad1618 [11]

Answer: 47.1/15

Step-by-step explanation:

We define Circumference by C= pie X D[diameter]

Hence pie= C/ D= 47.1/15

3 0
3 years ago
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