All categories

3 years ago

The perimeter of a square is 54 cm.Find the length of a diagonal, rounding to the nearest tenth

Mathematics

1 answer:

Kisachek [45]3 years ago

6 0

Answer:

19.09 = 19.1

Step-by-step explanation:

we can split the square into two right triangles. Becasue the perimeter of the square is 54cm, we know the each side is 13.5 cm (54cm / 4). Using the pythagoras theorem, the diagonal is 19.1 cm.

You might be interested in

Please help thank you

allochka39001 [22]

I think it's 20. Sorry if it's wrong

4 0

3 years ago

Choose all the numbers that are common multiples of 12 and four

irina [24]

Answer:

12, 24 , and 36

Step-by-step explanation:

6 0

3 years ago

A restaurant employs five people. The two cooks

shusha [124]

Answer:

Step-by-step explanation:

explain the question pls so I can help

6 0

3 years ago

Mr.Rhicardson has 34 boxes of chocolate in each box there are 123 chocolate bars. How much does he have in total?

Svet_ta [14]

A because 123×34=4,182

7 0

3 years ago

Read 2 more answers

Eric, Cam, and Brooke are playing a game of mini golf on a computer. The computer program for the game stores

andrew-mc [135]

Answer:

Eric

Step-by-step explanation:

First, we determine the distance of each player to the hole using the distance formula.

Given points $(x_1,y_1)$ and (x_2,y_2)$

Distance $=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Eric

The hole is at (3,2)

Eric's golf ball is at point (-6,6)

Distance= $\sqrt{(-6-3)^2+(6-2)^2}$

$=\sqrt{(-9)^2+(4)^2}\\=\sqrt{97} \\\approx 9.85$

Cam

The hole is at (3,2)

Cam's golf ball is at point (8,-6)

Distance= $\sqrt{(8-3)^2+(-6-2)^2}$

$=\sqrt{(5)^2+(-8)^2}\\=\sqrt{89} \approx9.43$

Brooke

The hole is at (3,2)

Brooke's golf ball is at point (10,8)

$Distance=\sqrt{(10-3)^2+(8-2)^2}\\=\sqrt{(7)^2+(6)^2}\\=\sqrt{85} \approx 9.22$

Since Eric's ball is the farthest from the hole, Eric should shoot next.

7 0

3 years ago