How does Shakespeare immediately introduce Tybalt as a menacing character?
1 answer:
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Answer:
Step by step explanation along with code and output is provided below
Explanation:
#include<iostream>
using namespace std;
// print_seconds function that takes three input arguments hours, mints, and seconds. There are 60*60=3600 seconds in one hour and 60 seconds in a minute. Total seconds will be addition of these three
void print_seconds(int hours, int mints, int seconds)
{
int total_seconds= hours*3600 + mints*60 + seconds;
cout<<"Total seconds are: "<<total_seconds<<endl;
}
// test code
// user inputs hours, minutes and seconds and can also leave any of them by entering 0 that will not effect the program. Then function print_seconds is called to calculate and print the total seconds.
int main()
{
int h,m,s;
cout<<"enter hours if any or enter 0"<<endl;
cin>>h;
cout<<"enter mints if any or enter 0"<<endl;
cin>>m;
cout<<"enter seconds if any or enter 0"<<endl;
cin>>s;
print_seconds(h,m,s);
return 0;
}
Output:
enter hours if any or enter 0
2
enter mints if any or enter 0
25
enter seconds if any or enter 0
10
Total seconds are: 8710
Complete question is attached as snapshot.
Answer:
This will result in a compilation error.
Here's the inheritance hierarchy:
Meg -> Lois -> Brian -> Stewie
Now Meg has 2 public Fxns, a() and toString().
Lois inherits from Meg and all its public functions as well but, overrides the a() fxn of its super class.
So finally Lois has fxns a(), b() and toString().
Brian extends Lois and inherits all the above listed fxns of Lois, but overrides the b() and toString() fxns.
Stewie extends Brian and inherits all the fxns of Brian, but overrides the a() and toString() fxns.
In the Main driver fxn, we call a() and b() methods of all these classes but, the base class Meg has no b() and it is not extending any class so its not available in its scope.
This results in a compilation error.
Explanation:
