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chubhunter [2.5K]
3 years ago
14

Find an equation of the line that passes through (6,-1) and has a slope of 3

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
5 0

Answer:

The equation is: y y = 5/4 * x - 13

Step-by-step explanation:

The slope-intercept y = mx + c form of a straight line is In this case we have a point, (x, y) and the slope, m so all we need is a value for c. Substitute into y = mx + c - 3 = 5/4 * (8) + c - 3 = 10 + c c = - 13 y = 5/4 * x - 13 The equation is: y the formula for the situation have a point, (x 1 ,y 1 ) and the slope, Or you can use where you (m) y-y 1 =m(x-x 1 ) y - (- 3) = 5/4 * (x - 8) y + 3 = 5/4 * x - 10 y = 5/4 * x - 13 Answer link < II

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Secant BE and CF intersect at point A inside D. What is the measure of BF?
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Answer:

\text{BF}=80^{\circ}

Step-by-step explanation:

We have been given a circle D. Secant BE and CF intersect at point A inside D. We are asked to find the measure of arc BF.

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m\angle EAF=\frac{\text{Measure of arc EF+Measure of arc BC}}{2}

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We know that degree measure of circumference of circle is 360 degrees, so we can set an equation as:

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\text{BF}=80^{\circ}

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A sum of money doubles in 20 years on simple interest. It will
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Step-by-step explanation:

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3 years ago
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