By connecting the distances traveled by the jet and the distance between them, we form a right triangle with hypotenuse equal to the unknown distance.
Using the Pythagorean,
h² = a² + b²
Substituting,
h² = (108 mi)² + (214 mi)²
h = 239.71 miles
Thus, the distance between them is approximately 239.71 miles.

7 0

3 years ago

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3sin60°+xcos30°.tan45°=xcot30°

Sliva [168]

Answer:

x = (6 $\sqrt{2}$ )/(4 $\sqrt{2}$ -3)

Step-by-step explanation:

sin60 degree = $\sqrt{3}$ /2

cos30 degree = 1/2

tan 45 degree = sin45 degree / cos45 degree = ( $\sqrt{2}$ /2)/( $\sqrt{2}$ /2) = 1

cot 30 degree = cos30 / sin30 = ( $\sqrt{3}$ /2)/(1/2) = $\sqrt{3}$

so, let us plug the above values in the given eqution and solve for x

3( $\sqrt{3}$ /2 ) + x(1/2) *1 = x( $\sqrt{3}$ )

3( $\sqrt{3}$ /2 ) = x( $\sqrt{3}$ ) -x(1/2)

3( $\sqrt{3}$ /2 ) = x(( $\sqrt{3}$ )-(1/2)) (by taking x as a common factor)

3( $\sqrt{3}$ /2 ) = x(((2 $\sqrt{3}$ )-(1))/2)) (making the same common denominator

now devide both sides by (((2 $\sqrt{3}$ )-(1))/2))

x = 3( $\sqrt{3}$ /2 ) / (((2 $\sqrt{3}$ )-(1))/2))

x = 3( $\sqrt{3}$ ) / ((2 $\sqrt{3}$ )-(1))

3 0

3 years ago