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3 years ago

Which method will NOT get you to the point (4,3.5)?

Mathematics

1 answer:

lesantik [10]3 years ago

3 0

Answer:

A. Starting at the origin, go 3.5 spaces to the right and then 4 spaces up.

Step-by-step explanation:

if you were to plot this then the point would be (3.5,4) instead of (4,3.5)

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The length of a rectangle is 3 1/6 cm longer than the width. The perimeter of the rectangle is 15 1/3 cm. What are the width and

Delicious77 [7]

The width of rectangle is $2\frac{1}{4}\ cm$ and length is $5\frac{5}{12}\ cm$

Step-by-step explanation:

Let,

Width of rectangle = w

Length of rectangle = w+ $3\frac{1}{6}=w+\frac{19}{6}$

Perimeter of rectangle = $15\frac{1}{3}=\frac{46}{3}\ cm$

Perimeter of rectangle = 2(Length + Width)

$2(w+\frac{19}{6}+w)=\frac{46}{3}\\2(2w+\frac{19}{6})=\frac{46}{3}\\4w+\frac{19}{3}=\frac{46}{3}$

Subtracting $\frac{19}{3}$ from both sides

$4w+\frac{19}{3}-\frac{19}{3}=\frac{46}{3}-\frac{19}{3}\\4w=\frac{46-19}{3}\\4w=\frac{27}{3}\\4w=9$

Dividing both sides by 4

$\frac{4w}{4}=\frac{9}{4}\\w=\frac{9}{4}$

Therefore,

Width of rectangle = w = $\frac{9}{4}=2\frac{1}{4}$ cm

Length of rectangle = $w+\frac{19}{6}=\frac{9}{4}+\frac{19}{6}=\frac{27+38}{12}=\frac{65}{12}=5\frac{5}{12}\ cm$

The width of rectangle is $2\frac{1}{4}\ cm$ and length is $5\frac{5}{12}\ cm$

Keywords: perimeter, addition

Learn more about addition at:

#LearnwithBrainly

7 0

4 years ago

Which values of <br> P<br> and <br> Q result in an equation with no solutions?<br> 83x+P=83x+Q

aleksandr82 [10.1K]

83x+P=83x+Q

subtract 83x from each side

P=Q

if P does not Q there are no solutions

the lines would be parallel and never intersect if Q does not equal P

6 0

3 years ago

If P is the incenter of triangle JKL, find the measure of JKP.

ladessa [460]

Answer:

m∠JKP = 31.5°

Step-by-step explanation:

Incenter of a triangle is the point where all the bisectors of interior angles intersect each other.

JN is the angle bisector of ∠KJL.

Therefore, m∠KJN = m∠LJN

(7x - 6) = (5x + 4)

7x - 5x = 6 + 4

2x = 10

x = 5

m∠KJN = (7x - 6)

= 7(5) - 6

= 35 - 6

= 29°

In ΔKJN,

m∠JKN + m∠KNJ + m∠NJK = 180°

m∠JKN + 90° + 29° = 180°

m∠JKN = 180°- 119° = 61°

Since KO is the angle bisector of ∠JKN,

m∠JKP = $\frac{1}{2}(\angle JKN)$

= $\frac{1}{2}(61)$

= 30.5°

6 0

3 years ago

Using the drawing tool, graph the two inequalities on the number line. Take a screenshot of each number line and submit it in th

masya89 [10]

Zero on number lines is neither negative nor positive, it is used as a sort of divider number;)

Step-by-step explanation: this picture should help explain a little

4 0

3 years ago

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A rectangle school banner has a length of 44 inches, a perimeter of 156 inches , and an area of 1496 square inches. The cheerlea

kakasveta [241]

Since you have the length and the area, you can assume the width

1496/44 = Width Because Area = L * W

Width = 34

So this is a ratio problem

44/11 = ratio

So, the ratio is 4:1
So since we have the width, we can divide the width of the school banner by 4 because of the scale

34/4 = 8.5 = width of the sign

The area of the sign is 8.5*11 = 93.5

and the perimeter is just that,

8.5 * 2 + 11*2 = 39

Perimeter = 39 inches

Area = 93.5 inches²

3 0

3 years ago

Read 2 more answers