Answer:
carnation $2.50; rose $3.00
Step-by-step explanation:
Let c = price of 1 carnation.
Let r = price of 1 rose.
3c + 5r = 22.5
3c + 2r = 13.50
Subtract the se3cond equation from the first equation.
3r = 9
r = 3
Now substitute r = 3 in the first equation and solve for c.
3c + 5r = 22.5
3c + 5(3) = 22.5
3c = 7.5
c = 2.5
Answer: carnation $2.50; rose $3.00
Answer:
45,9
Step-by-step explanation:
Answer:
31.4 inches
Step-by-step explanation:
:))
now, there are 12 months in a year, so 18 months is really 18/12 of a year, thus
![~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$4000\\ P=\textit{original amount deposited}\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ t=years\to \frac{18}{12}\dotfill &\frac{3}{2} \end{cases} \\\\\\ 4000=P[1+(0.05)(\frac{3}{2})]\implies 4000=P(1.075) \\\\\\ \cfrac{4000}{1.075}=P\implies 3720.93\approx P](https://tex.z-dn.net/?f=~~~~~~%20%5Ctextit%7BSimple%20Interest%20Earned%20Amount%7D%20%5C%5C%5C%5C%20A%3DP%281%2Brt%29%5Cqquad%20%5Cbegin%7Bcases%7D%20A%3D%5Ctextit%7Baccumulated%20amount%7D%5Cdotfill%20%26%20%5C%244000%5C%5C%20P%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5C%5C%20r%3Drate%5Cto%205%5C%25%5Cto%20%5Cfrac%7B5%7D%7B100%7D%5Cdotfill%20%260.05%5C%5C%20t%3Dyears%5Cto%20%5Cfrac%7B18%7D%7B12%7D%5Cdotfill%20%26%5Cfrac%7B3%7D%7B2%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%204000%3DP%5B1%2B%280.05%29%28%5Cfrac%7B3%7D%7B2%7D%29%5D%5Cimplies%204000%3DP%281.075%29%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B4000%7D%7B1.075%7D%3DP%5Cimplies%203720.93%5Capprox%20P)
That's not a squre
anyway, we use ratios
base:person to corner=28:8
height to height=x:5
so
28/8=x/5 becasue same ratio
28/8=14/4=7/2
7/2=x/5
multiply
35/10=2x/10
35=2x
divide 2
17.5=x
x=17.5 feet
