Answer:
Probability of having two hits in the same region = 0.178
mu: average number of hits per region
x: number of hits
e: mathematical constant approximately equal to 2.71828.
Step-by-step explanation:
We can describe the probability of k events with the Poisson distribution, expressed as:

Being μ the expected rate of events.
If 535 bombs hit 553 regions, the expected rate of bombs per region (the events for this question) is:

For a region to being hit by two bombs, it has a probability of:

Answer:
124
Step-by-step explanation:
Answer:
Sorry what is the equation because i can not read what you put it like you are mixing number with other number that i can not read like this
Step-by-step e
Answer:
ok in this case will represent the height with a the bells with b and the hypotenuse with c so it will be c squared is equals to a squared plus b squared 12 squared + 5 squared is equals to c squared 12 square is 144 while 5 squared is 25 when added it is 169 so csquared is equals to 169 to get c we find √ 169 source is equals to 13