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katrin2010 [14]
2 years ago
11

Find x and y intercepts y=(2x+10)(x-2)

Mathematics
1 answer:
slega [8]2 years ago
8 0

Step-by-step explanation:

y = (2x + 10)(x - 2)

y = 2x(x - 2) + 10(x - 2)

y = 2x ^{2}  - 4x + 10x - 20

y = 2x ^{2}  + 6x - 20

to \: find \: x \: intercept \: y = 0

0 = 2x ^{2}  + 6x - 20

x = 2 \: or \:  - 5

to \: find \: y \: intercept \: x = 0

y = 2(0)^{2}  + 6(0) - 20

y =  - 20

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To make the graph, locate the previous points on the coordinate plane and then draw the line that passes through them (see figure attached)

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7 0
2 years ago
which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1​
lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. y=\sec x

B. y= \tan x

C. y= \cot x

D. y= \csc x

Answer:

A. y=\sec x

D. y=\csc x

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: y=\sec x

We know that, the \sec x=\frac{1}{\cos x}

The range of \cos x is from -1 to 1 given as [-1, 1]. So,

|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1

Therefore, on removing the absolute sign, we rewrite the secant function as:

\sec x\leq -1\ or\ \sec x\geq 1\\

Therefore, the range of y=\sec x is all real numbers greater than or equal to 1 or less than or equal to-1​.

Choice B: y= \tan x

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: y= \cot x

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: y=\csc x

We know that, the \csc x=\frac{1}{\sin x}

The range of \sin x is from -1 to 1 given as [-1, 1]. So,

|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

\csc x\leq -1\ or\ \csc x\geq 1\\

Therefore, the range of y=\csc x is all real numbers greater than or equal to 1 or less than or equal to-1​.

6 0
3 years ago
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Answer:

Step-by-step explanation:

5 0
2 years ago
Help me so confused?
Eva8 [605]

BD is 31 degrees because it is the same.

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7 0
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