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Sav [38]
2 years ago
11

An airplane is flying from knoxville to new york. The distance it travels in miles, d, is related to the time in seconds, t, by

the equation: d=0.12t. How many miles is it flying per second?
Mathematics
1 answer:
Zigmanuir [339]2 years ago
5 0

Answer:

0.12 miles is it flying per second.

Step-by-step explanation:

The distance d is related to time t in seconds is given by the equation as follows :

d =0.12 t

We need to find how many miles is it flying per second.

\dfrac{d}{t}=0.12\\\\\dfrac{\text{miles}}{\text{second}}=0.12

So, the speed of the airplane is 0.12 miles per second, Hence, 0.12 miles is it flying per second.

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madam [21]

Answer:

2.1%

Step-by-step explanation:

The formula for compound interest is given as:

A=P(1+I)^n\\\\P-Principal \\A-amount\\i-compound \ interest \ rate

Given the Principal amount as $6000, and the rate in the first two years as 1.5%:

A=P(1+i)^n\\\\A_2=6000(1+0.015)^2\\\\A_2=6181.35

We compound A_2 for 1 year at rate i to obtain $6311.16:

A=P(1+i)^n, n=1, i=i, P=6181.35, A=6311.16\\\\6311.16=6181.35(1+i)^1\\\\\frac{6311.16}{6181.35}=(1+i)\\\\i=\frac{6311.16}{6181.35}-1\\\\i=0.02100

Hence, the compound interest rate in the third year is 2.1%

7 0
3 years ago
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Sarah rode her bike 53 km in 4 hours.
Igoryamba
Its just 53/4 it gives you km/h, 13.25 km/h
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3 years ago
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What is the length of the hypotenuse?
Rainbow [258]

Answer:

Hello! answer: 58

Step-by-step explanation:

40 × 40 = 1600

42 × 42 = 1764

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58 × 58 = 3364 therefore c = 58 Hope that helps!

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2 years ago
I WILL GIVE BRAINLIEST TO WHOEVER IS CORRECT
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The second one should by right
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Regular hexagon ABCDEF rotates 240° counterclockwise about its center to produce hexagon A'B'C'D'E'F'. Which points will A' and
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To answer this specific problem, the points that A’ and B’ will coincide with in the preimage is “A' coincides with E and B' coincides with D.” The correct answer between all the choices given is the third choice or letter C. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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