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Anon25 [30]
2 years ago
7

A=2(L+W) (w) can some one help me

Mathematics
1 answer:
Lelu [443]2 years ago
7 0

Answer:

2Lw+2Ww

Step-by-step explanation:

you multiply the ones outside which are

2 and w

to give '2w'

then,

2w(L+W)

you expand the bracket by multiplying each term in it by 2w thus:

2w*L +2w*W

=2wL+2wW

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Tyra made 8 fewer jackets than zack they made 48 jackets altogether how many jackets did zac make
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Answer:

Zac Made 28 Jackets

Step-by-step explanation:

The way I solved it is by first dividing 48 by 2.

After that I subtracted 8 from Tyra's jackets and then guessed and checked.

I eventually got to the point where i found that Tyra made 20 jackets and Zac made 28 making up to 48 jackets in total.

3 0
3 years ago
The waitress and the hostess at a restaurant share the tips at the end of the shift the average amount earned in tips between th
soldi70 [24.7K]
The waitress will get 120 dollars

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Can someone help please
Naddika [18.5K]

Answer:

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Step-by-step explanation:

If you divide 64 by 8 then you get 8 and if you divide 40 by 5 you also get 8.

3 0
2 years ago
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What is the approximate volume of the cylinder use 22/7 for 3.14 round to the nearest whole number
erastova [34]

Answer:

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Step-by-step explanation:

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5 0
2 years ago
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Find the minimum sample size needed to estimate the percentage of Democrats who have a sibling. Use a 0.1 margin of error, use a
Brums [2.3K]

Answer:

The minimum sample size is  n  =135

Step-by-step explanation:

From the question we are told that

   The confidence interval is ( lower \ limit  = \  0.44,\ \ \   upper \ limit  = \ 0.51)

    The margin of error is  E =  0.1

   

Generally the sample  proportion can be mathematically evaluated as

     \r p = \frac{ upper \ limit  + lower \ limit }{2}

    \r p = \frac{ 0.51 + 0.44}{2}

    \r p = 0.475

Given that the confidence level is  98% then the level of significance can be mathematically evaluated as

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        \alpha = 2\%

        \alpha =0.02

Next we obtain the critical value of  \frac{\alpha }{2} from the normal distribution table  

   The value is

        Z_{\frac{\alpha }{2} } =  2.33

Generally the minimum sample size is evaluated as

      n  =[ \frac { Z_{\frac{\alpha }{2} }}{E} ]^2 *  \r p (1- \r p )

     n  =[ \frac { 2.33}{0.1} ]^2 *  0.475(1- 0.475 )

     n  =135

6 0
3 years ago
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