There are 60 minutes in an hour. 6x10=60. if 6*10=50, and there are 1.5 mi per every 10 minutes, we multiply 1.5 times 6 to get our answer, which is 9.
our answer is 9, i think
Smallest:x-2
middle:x
biggest:x+2
smallest+middle=biggest=(x-2)+(x)+(x+2)=3x
3x=192->3x/3=192/3->x=64
smallest: 64-2=62
One form of the equation of a vertical parabola is y = x^2, which is the same as y-0 = a(x-0)^2.
If the coefficient a is positive, the parabola opens up. If a is - the parabola opens down.
The vertex of this parabola is (0,0).
More generally, y - k = a(x - h)^2 represents a vertical parabola that opens up if a is + and opens down if a is - and has its vertex at (h,k).
Often a = 1. If a is greater than 1, the graph of the parabola is stretched vertically; if less than 1, the graph is compressed vertically (and thus appears to be flatter).
y - k = a(x - h)^2 is called the 'general vertex form' of a vertical parabola.
This is a quadratic equation. With some algebra, we could rewrite
y - k = a(x - h)^2 in the form y = ax^2 + bx + c.
x-intercepts of this parabola, if any, can be found using the quadratic formula, involving the constant coefficients a, b and c.
Answer:
dy/dt = 8
Step-by-step explanation:
y = 2x^3 -4x
dy/dt = 2 * 3x^2 dx/dt -4 dx/dt
dy/dt = 6x^2 dx/dt - 4 dx/dt
substitute dx/dt =4 and x=1
dy/dt = 6 * (1)^2 * 4 - 4(4)
dy/dt = 24-16
dy/dt = 8
Answer:
f(42) = 12
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = x/3 - 2
f(42) is x = 42
<u>Step 2: Evaluate</u>
- Substitute in <em>x</em>: f(42) = 42/3 - 2
- Divide: f(42) = 14 - 2
- Subtract: f(42) = 12
