Ask question

Ask question

All categories

3 years ago

12

Lucas deposits $4,000.00 for 6 years at 2% interest, compounded monthly. How much interest does he earn at the end of the 6 year

s? Round to the nearest cent. SHOW THE WORK PLEASE

2 answers:

kow [346]3 years ago

8 0

Answer:

Step-by-step explanation:

$A=P(1+r/c)^{ct}\\ \\ A=4000(1+.02/12)^{12(6)}\\ \\ A\approx \$ 4509.54$

Rudik [331]3 years ago

6 0

Answer:

$12644.56

Step-by-step explanation:

one year = 12 month

4,000 * (1.02)^(6*12) = 16644.5615

16644.5615-4000 = 12644.5615

You might be interested in

Please Help!!!!!!! No stupid answers

Snowcat [4.5K]

A. The ratio of the person's shadow to their height is 6:2 or 3:1, so the height of the shadow is 360/3 or 120 m.
B. The model car's length divided by the ratio to the real car, which is 8.5/0.8 = 10.625 cm long.

6 0

3 years ago

Read 2 more answers

A lady walks in the store and steals $100 bill from the register without the owners knowledge. She comes back 5 minutes later an

sergeinik [125]

$170
100+70 is your answer

7 0

4 years ago

Read 2 more answers

SO basically uhh I suck at math

postnew [5]

Ok so you plug them in. -5 squared is 25 minus 27

6 0

3 years ago

Read 2 more answers

In the lake, a sailboat casts a shadow of 4 yards. A buoy that is 2 feet tall casts a shadow of 1 foot. What is the height of th

morpeh [17]

First you would find that not all the units are the same in this problem, so you convert yards to feet. So 4 yards = 12 feet.

The proportion you would make would be x/12 = 2/1

7 0

3 years ago

Read 2 more answers

Use technology or a z-score table to answer the question.

Alik [6]

Answer:

The second choice: Approximately $65.2\%$ of the pretzel bags here will contain between 225 and 245 pretzels.

Step-by-step explanation:

This explanation uses a z-score table where each $z$ entry has two decimal places.

Let $\mu$ represent the mean of a normal distribution of variable $X$ . Let $\sigma$ be the standard deviation of the distribution. The z-score for the observation $x$ would be:

$\displaystyle z = \frac{x - \mu}{\sigma}$ .

In this question,

$\mu = 240$ .
$\sigma = 9.3$ .

Calculate the z-score for $x_1 = 225$ and $x_2 = 245$ . Keep in mind that each entry in the z-score table here has two decimal places. Hence, round the results below so that each contains at least two decimal places.

$\begin{aligned} z_1 &= \frac{x_1 - \mu}{\sigma} \\ &= \frac{225 - 240}{9.3} \approx -1.61\end{aligned}$ .

$\begin{aligned} z_2 &= \frac{x_2 - \mu}{\sigma} \\ &= \frac{245 - 240}{9.3} \approx 0.54\end{aligned}$ .

The question is asking for the probability $P(225 \le X \le 245)$ (where $X$ is between two values.) In this case, that's the same as $P(-1.61 \le Z \le 0.54)$ .

Keep in mind that the probabilities on many z-table correspond to probability of $P(Z \le z)$ (where $Z$ is no greater than one value.) Therefore, apply the identity $P(z_1 \le Z \le z_2) = P(Z \le z_2) - P(Z \le z_1)$ to rewrite $P(-1.61 \le Z \le 0.54)$ as the difference between two probabilities:

$P(-1.61 \le Z \le 0.54) = P(Z \le 0.54) - P(Z \le -1.61)$ .

Look up the z-table for $P(Z \le 0.54)$ and $P(Z \le -1.61)$ :

$P(Z \le 0.54)\approx 0.70540$ .
$P(Z \le -1.61) \approx 0.05370$ .

$\begin{aligned}& P(225 \le X \le 245) \\ &= P\left(\frac{225 - 240}{9.3} \le Z \le \frac{245 - 240}{9.3}\right)\\&\approx P(-1.61 \le Z \le 0.54) \\ &= P(Z \le 0.54) - P(Z \le -1.61)\\ &\approx 0.70540 - 0.05370 \\& \approx 0.65.2 \\ &= 65.2\% \end{aligned}$ .

3 0

3 years ago