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3 years ago

−39 = −0.6k what does k equal

Mathematics

2 answers:

denis-greek [22]3 years ago

4 0

Answer: k=65

Step-by-step explanation:

joja [24]3 years ago

3 0

Answer:

k=65

Step-by-step explanation:

You would need to divide -0.6 on both sides to isolate k

-39 = -0.6k Original equation

-39÷ -0.6 = -0.6k÷-0.6 Isolating the variable

-39÷-0.6 = k SImplification

65 = k The answer!!!

When multiplying or dividing 2 negative numbers, remember that the result will be positive

I hope this helps!!!

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Find the cost of painting a cubical block of side length 3.2 cm, if painting costs $5 per cm2.

SashulF [63]

<h3>Answer:- </h3>

$\longrightarrow \sf \$ \: 307.2$

<h3>Solution:-</h3>

Since painting is done on outer surface of cubical block we will have to find its surface area which is given by-

$\green{ \underline { \boxed{ \sf{Surface \: area \:of \:Cube = 6a^2}}}}$

where a is side of the cube

$\begin{gathered}\\\quad \sf Surface \: area \:of \:Cube = 6\times(3.2)^2 \\\end{gathered}$

$\begin{gathered}\\\implies \quad \sf 6\times 3.2\times3.2 \\\end{gathered}$

$\begin{gathered}\\\implies \quad \sf 61.44 cm^2 \\\end{gathered}$

Now,

$\maltese \sf Cost \:of \:painting \: 1 \: cm² = \$ 5$

$\sf Cost \: of \: painting \: 61.44 \:cm²=61.44×5$

$\sf\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad=\$ 307.2$

$\leadsto$ Thus it would cost $ 307.2 to paint the entire cubical block.

3 0

3 years ago

URGENT NEED HELP CLICK TO SEE

Phantasy [73]

Answer:

Step-by-step explanation:

Can I have Brainliest? I hope this helped and have a nice day!!!

Work:

64 / 2 = 32

3/4 / 2 = 3/8

3/4 = 6/8

6/8 / 2 = 3/8

Final answer 32 3/8

3 0

3 years ago

a wire of length 200 cm is cut into two parts and each part is bent to form a square.If the area of the larger square is 9 times

diamong [38]

Answer:

The perimeter of the larger square is $150cm.$

Step-by-step explanation:

First of all, let one part of it be " $x$ "

and the other part of it " $200-x$ "

Now to solve this :

The area of the square = $L^2$

The area of one part of the square = $x^2$

The area of the other part of the square = $(200-x)^2$

$9x^2= (200-x)^2\\9x^2=40000-400x+x^2$

Now, add, $-4x^2$ to both the sides :

$9x^2-9x^2=40000-400x+x^2-9x^2\\-1(8x^2+400x-40000)=0$

Now, take out the "8" which is common :

$-8(x^2+50x-5000)=0$

Now, divide it by $-8$ :

$x^2+100x-50x-5000=0\\x(x+100)-50(x+100)=0\\(x+100)(x-50)=0\\$

$x=-100$ or $50$

So, now we know that :

One of the part is = $50cm$

And the other part is = $150cm$

Thus the perimeter of the larger square is = $150cm$

3 0

3 years ago

The sum of the first 15 terms of a geometric sequence with 7 as the first term and a common ratio of -3 is __________.

Andre45 [30]

Step-by-step explanation:

the formula for the sum of the first n terms of a geometric sequence is

Sn = s1(1 - r^n)/(1 - r)

with r being the common ratio and s1 is the first term.

so,

S15 = 7×(1 - (-3)¹⁵)/(1 - -3) = 7×(1 - -14,348,907)/4 =

= 7×14,348,908/4 = 7×3,587,227 = 25,110,589

4 0

2 years ago

Can someone help me pls

FrozenT [24]

There are 4 lateral faces that are triangles. Each triangle is: A = $\frac{b x h}{2}$
A = $\frac{16 x 22}{2}$
   = 176

There is one base that is a square. A = L x W
A = 16 x 16
   = 256

Surface area = 256 + 4(176)
                     = 256 + 704
                     = 960

Answer: B

8 0

3 years ago

Read 2 more answers