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enyata [817]
2 years ago
10

Factories 2x^3+ 7x^2+ 7x +2 emergency pls ​

Mathematics
2 answers:
RoseWind [281]2 years ago
8 0

Answer:

the answer is (x+1)(x+2)(2x+1)

Rom4ik [11]2 years ago
4 0

hope it helps you...............

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What are the solutions of the equation x^4 + 6x^2 + 5 = 0? Use u substitution to solve.
Radda [10]

Answer:

second option

Step-by-step explanation:

Given

x^{4} + 6x² + 5 = 0

let u = x², then

u² + 6u + 5 = 0 ← in standard form

(u + 1)(u + 5) = 0 ← in factored form

Equate each factor to zero and solve for u

u + 1 = 0 ⇒ u = - 1

u + 5 = 0 ⇒ u = - 5

Change u back into terms of x, that is

x² = - 1 ( take the square root of both sides )

x = ± \sqrt{-1} = ± i ( noting that \sqrt{-1} = i ), and

x² = - 5 ( take the square root of both sides )

x = ± \sqrt{-5} = ± \sqrt{5(-1)} = ± \sqrt{5} × \sqrt{-1} = ± i\sqrt{5}

Solutions are x = ± i and x = ± i\sqrt{5}

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3 years ago
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Step-by-step explanation:

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Please show me all of the steps for multiplying 10×.25
trapecia [35]
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_____
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the answer is 2.5


6 0
3 years ago
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