Answer:
There can be at most
attendees in a corporate team-building event.
Step-by-step explanation:
Let
denotes number of attendees in a corporate team-building event.
Fixed cost = $19
Cost charged per attendee = $1
Budget for the corporate team-building event = $31
Therefore,

So, there can be at most
attendees in a corporate team-building event.
Answer:
Step-by-step explanation:
f(x) = (1/2) *6^x = 2^-1 * 2^x *3^x
y= 2^ (x-1) * 3^x
Domain represents all values that x can have and is all real numbers
Range all values that y can have and is y > 0 ( all real numbers that are positive)
The y-intercept is the point where the graph intersects the y-axis so x=0 there
y = 2^(0-1) *3^0 = 1/2 *1 = 1/2
the asymptote is at y= 0
Answer:
160 cars
Step-by-step explanation:
The computation of the number of more cars he washed this year is given below;
Last year, he washed 20 cars a week so on yearly basis he washed
= 20 cars × 52 weeks
= 1,040 cars
And, this year he washed 1,200 cars
So, the number of more cars he washed this year is
= 1,200 cars - 1,040 cars
= 160 cars
Answer:
The answer is 3.64m
This is because if you draw a diagram, and label all the sides of the triangle (opp, hyp, adj), the adjacent angle is 3m. You can now use the sine rule to find the hypotenuse (length of ladder) by doing: cos 30= 3/h. You divide cos 30 by 3 and you get the answer of 3.64m rounding to 2 decimal places.
The solutions of the equations are -1.3 and -7.7
Step-by-step explanation:
The quadratic formula of solving the quadratic equation
ax² + bx + c = 0, where a, b and c are constant is:
To solve the quadratic equation by using the quadratic formula
1. Find the values of a , b and c from the equation
2. Substitute the values of a , b and c in the quadratic formula
3. Find the two values of x
∵ x² + 9x + 10 = 0
∴ a = 1 , b = 9 and c = 10
∵ 
∴ 
∴ 
∴ x = -1.3
∵ 
∴ 
∴ 
∴ x = -7.7
The solutions of the equations are -1.3 and -7.7
Learn more:
You can learn more about quadratic equation in brainly.com/question/8196933
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