Can you divide a donut into 5 pieces (doesn't have to be equal)? If so could you explain or draw a diagram. using 2 straight cut
2 answers:
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The answers are
11. c) 7x² +5x +8 remainder 7.
12. d) 6x² -6x +3 remainder 2x.
Step-by-step explanation:
Step 1; By dividing 7x³ -2x² +3x -1 with x -1 we get the following calculations. We multiply 7x² with x-1 and get 7x³ - 7x². We subtract this from 7x³ -2x² and get 5x². Now we add this with the 3x in 7x³ -2x² +3x -1. We get 5x² +3x. We multiply x -1 with 5x and get 5x² -5x and subtract it from 5x² +3x and get 8x. We multiply the x -1 with 8 and get 8x -8. We subtract this from 8x -1 and get a remainder of 7. So the quotient is 7x² +5x +8 with a remainder of 7.
Step 2; By dividing 6 +0x³ -3x² +5x with x² +x we get the following calculations. We multiply 6x² with x² +x and get 6
+6x³. We subtract this from 6
+0x³ and get -6x³. Now we add this with the -3x² in 6
+0x³ -3x² +5x. We get -6x³ -3x². We multiply x² +x with -6x and get -6x³ -6x² and subtract it from -6x³ -3x² and get 3x². We multiply the x² +x with 3 and get 3x² +3x. We subtract this from 3x² +5x and get a remainder of 2x. So the quotient is 6x² -6x +3 with a remainder of 2x.
Answer:
1) 11h - 25
2) 8
3) C
Step-by-step explanation:
1) 5h-9+-16+6h
+ and - together makes -
5h - 9 - 16 + 6h
Arrange the like terms together
5h + 6h - 9 - 16
= 11h - (9+16)
= 11h - 25
2) 4x+4=9x-36
Subtract 4x from both sides
4x+4-4x = 9x-36-4x
Cancl out 4x and -4x from the left side
4 = 9x - 4x -36
=> 4 = 5x -36
Add 36 to both sides
4+36 = 5x -36 + 36
Cancel out -36 and +36 from the right side
=> 40 = 5x
Flip both the sides of the equation
5x = 40
Dividing both sides by 5
Cancel out the 5's on the top and bottom of the left side
x = 8
3) 7x+5 = 4x+5+3x
Arrange the like terms together on the right side
7x+5 = 4x+3x+5
=> 7x+5 = 7x+5
Subtract 5 from both sides
7x+5-5 = 7x+5-5
Cancel out +5 and -5 on both the sides
7x = 7x
Divide both sides by 7
Cancel out the 7's from the top and bottom of both sides
x = x
which can be true for infinite value of x like 1=1, 2=2, 3=3,.............