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3 years ago

14

Stuart paid $48.00 for a new tennis racket, which was 64% of the original price. how much was the original price of the racket?

1 answer:

tester [92]3 years ago

4 0

I think its my as$ 12.3

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B(n)=−4−2(n−1)<br> What's the 12th term in the sequence?

marysya [2.9K]

The 12th term in the sequence is -26.

Given,

B (n) = -4 – 2(n – 1)

We have to find the 12th term in the sequence:

To find the nth term in an arithmetic sequence:

An arithmetic sequence's nth term is determined by the formula a = a + (n - 1)d. The common difference, or d, is the difference between any two consecutive terms in an arithmetic series; it can be calculated by deducting any pair of terms starting with a and an+1.

Here,

First term, a = -4

Common difference, d = -2

nth term = 12

Now, let’s find 12th term

B(n) = -4 -2(n – 1)

B(12) = -4 – 2(12 – 1)

B(12) = -4 -2(11)

B(12) = -4 -22

B(12) = -26

That is, the 12th term in the sequence is -26.

Learn more about arithmetic sequence here:

brainly.com/question/11570734

#SPJ1

8 0

1 year ago

PLS HELP WILL GIVE BRAINLIEST

frozen [14]

Answer:

3.5
2
B
A

Step-by-step explanation:

Middle School:

Find the median by arranging the data points from smallest to largest.

1, 1, 1, 3, 4, 4, 5, 6 (Take the average of the two points in the middle, 3 and 4)

7/2 = 3.5

High School:

1, 1, 1, 1, 2, 2, 2, 2, 3, 3, 3, 4 (Take the average of the two points in the middle, 2 and 2)

4/2 = 2

Most of the points in the middle school plot are four or less.

A (High school students had more variation.)

3 0

2 years ago

Match solutions and differential equations. Note: Each equation may have more than one solution. Select all that apply. (a) 7y''

Nonamiya [84]

Answer:

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

Step-by-step explanation:

a.7 y''-7 y =0

Auxillary equation

$D^2-1=0$

$(D-1)(D+1)=0$

D=1,-1

Then , the solution of given differential equation

$y=e^x,y=e^{-x}$

2. $7x^2y''+14xy'-14 y=0$

Y= $y=x^3$

$y=3x^2$

$y''=6x$

Substitute in the given differential equation

$42x^3+42x^3-14x^3\neq 0$

Hence, $x^3$ is not a solution of given differential equation

$e^x,e^{-x}$ are also not a solution of given differential equation.

y= $x^{-2}$

$y'=-2x^{-3}$

$y''=6x^{-4}$

Substitute the values in the differential equation

$7x^2(6x^{-4})+14x(-2x^{-3})-14 x^{-2}$

= $42x^{-2}-28x^{-2}-14x^{-2}=0$

Hence, $x^{-2}$ is a solution of given differential equation.

c. $7x^2y''-42y=0$

$y=x^3$

$y'=3x^2$

$y''=6x$

Substitute the values in the differential equation

$42x^3-42x^3=0$

Hence, $x^3$ is a solution of given differential equation.

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

6 0

3 years ago

Read 2 more answers

An anatomy model of an adult human is 7 inches tall. Most adult humans are between 5 feet and 6 feet tall. What is the approxima

anyanavicka [17]

Answer:

9.42857142857 inches = 1 inch

Step-by-step explanation:

12 inches in a foot

12 × 5.5 = 66

66 / 7 = 9.42857142857

3 0

3 years ago

Read 2 more answers

What is the common binomial factor of 5x(x+7) +3 (x+7)

son4ous [18]

Answer:

(x+7) (5x+3)

Step-by-step explanation:

that's what I got

3 0

3 years ago