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castortr0y [4]
3 years ago
11

I need help I can’t solve this problem

Mathematics
2 answers:
egoroff_w [7]3 years ago
7 0
Which one do you need help with

nikdorinn [45]3 years ago
5 0
Whuch one do you need help with
You might be interested in
Select the equation of the line parallel to the equation y = -2x - 7 that passes through the point (3, 1). y = -2x + 7 y = -2x +
Vilka [71]
Y - y₁ = m(x - x₁)
 y - 1 = -2(x - 3)
 y - 1 = -2(x) + 2(3)
 y - 1 = -2x + 6
   + 1          + 1
      y = -2x + 7

The answer is A.

7 0
3 years ago
Pls help quick will put brainliest
Olin [163]

Answer:

m<SQP=124°

Step-by-step explanation:

Hi there!

We're given ΔQRS, the measure of <R (90°), and the measure of <S (34°)

we need to find m<SQP (given as x+72°)

exterior angle theorem is a theorem that states that an exterior angle (an angle on the OUTSIDE of a shape) is equal to the sum of the two remote interior angles (the angle OUTSIDE of a shape will be equal to the sum of 2 angles that are OPPOSITE to that angle).

that means that m<SQP=m<R+m<S (Exterior angle theorem)

substitute the known values into the equation

x+72°=90°+34° (substitution)

combine like terms on both sides

x+72°=124° (algebra)

subtract 72 from both sides

x=52° (algebra)

however, that's just the value of x. Because m<SQP is x+72°, add 52 and 72 together to get the value of m<SQP

m<SQP=x+72°=52°+72°=124° (substitution, algebra)

Hope this helps!

4 0
3 years ago
Please help!! Solve the equation by graphing the related function. If the equation has no real-number solution, write no solutio
MrMuchimi
This equation has no solution
3 0
3 years ago
The diagonals of a quadrilateral must be bisect each other and be perpendicular to gurarantee that the quadrilateral is a parrel
morpeh [17]

Answer:

False

Step-by-step explanation:

A quadrilateral is a closed geometrical figure that have four sides and four vertices. Thus the following includes in a quadrilateral : parallelogram, square, rhombus, rectangle and trapezium.

If the diagonals of the quadrilateral bisects each other and are perpendicular to each other, then the quadrilateral forms a rhombus.

Hence the answer is FALSE.

4 0
3 years ago
Assume the random variable X is normally distributed with mean mu equals 50 and standard deviation sigma equals 7. Compute the p
drek231 [11]

Answer:

The probability that <em>X</em> is less than 42 is 0.1271.

Step-by-step explanation:

The random variable <em>X </em>follows a Normal distribution.

The mean and standard deviation are:

E (X) = <em>μ</em> = 50.

SD (X) = <em>σ</em> = 7.

A normal distribution is continuous probability distribution.

The Normal probability distribution with mean µ and standard deviation σ is given by,

f_{X}(\mu, \sigma)=\frac{1}{\sigma\sqrt{2\pi}}e^{-(x-\mu)^{2}/2\sigma^{2}};\ -\infty

To compute the probability of a Normal random variable we first standardize the raw score.

The raw scores are standardized using the formula:

z=\frac{x-\mu}{\sigma}

These standardized scores are known as <em>z</em>-scores and they follow normal distribution with mean 0 and standard deviation 1.

Compute the probability of (X < 42) as follows:

P(X

*Use a <em>z</em>-table for the probability.

Thus, the probability that <em>X</em> is less than 42 is 0.1271.

The normal curve is shown below.

6 0
4 years ago
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