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bonufazy [111]
3 years ago
5

The perimeter of the rectangular room is 96 feet. If the length is 6 feet more than the width, find the dimensions of the room.

Mathematics
1 answer:
n200080 [17]3 years ago
5 0

Answer:

27ft by 21ft

Step-by-step explanation:

In this particular question, we are made to know that the length is 6ft longer than the width.

This mathematically means that if the length is Xft, the width would be (x-6)ft

Since the shape is a rectangle, we know that P = 2(L + B )

Applying this to the measurements we have,

2( x + x - 6) = 96

4x - 12 = 96

4x = 12 + 96

4x = 108

x = 108/4 = 27

Since x = length = 27

width = x - 6 = 27 - 6 = 21

Hence, the dimension of the rectangular room is 27ft by 21ft

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Answer:

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Step-by-step explanation:

Given that; QT = 9 and TP = 8.

From the diagram, join R to P. Thus RP = QP (radius of the circle)

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Applying Pythagoras theorem to triangle TRP;

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3 years ago
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