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bonufazy [111]
4 years ago
5

The perimeter of the rectangular room is 96 feet. If the length is 6 feet more than the width, find the dimensions of the room.

Mathematics
1 answer:
n200080 [17]4 years ago
5 0

Answer:

27ft by 21ft

Step-by-step explanation:

In this particular question, we are made to know that the length is 6ft longer than the width.

This mathematically means that if the length is Xft, the width would be (x-6)ft

Since the shape is a rectangle, we know that P = 2(L + B )

Applying this to the measurements we have,

2( x + x - 6) = 96

4x - 12 = 96

4x = 12 + 96

4x = 108

x = 108/4 = 27

Since x = length = 27

width = x - 6 = 27 - 6 = 21

Hence, the dimension of the rectangular room is 27ft by 21ft

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D = 45 + 6c
165 = 45 + 6c
120 = 6c
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so he must sell 20 crates
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Answer:

<em>y=-0.2x+5. Correct choice: A)</em>

Step-by-step explanation:

<u>Modeling With Equations</u>

Let's call x the number of minutes and y the distance from home. The correct model should meet both conditions:

After 5 minutes, Ye is 4 miles from home. This is the ordered pair (5,4)

After 15 minutes, Ye is 2 miles from home. This is the ordered pair (15,2)

A) y=-0.2x+5. Testing the first point (5,4): y=-0.2*5+5=4. Correct

Testing the second point (15,2): y=-0.2*15+5=2. Correct

This is the correct choice.

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Testing the second point (15,2). y=11/7*15-27/7=138/7. Incorrect

Incorrect choice.

C) This equation is equal to the choice B), thus this one is incorrect.

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Hello there love
The sequace is taking 10 away
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MAXImum [283]

Answer:

50

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4 0
3 years ago
Evaluate the surface integral. s (x + y + z) ds, s is the parallelogram with parametric equations x = u + v, y = u − v, z = 1 +
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S is given to be parameterized by

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with 0\le u\le3 and 0\le v\le2. We have

\mathbf r_u=\langle1,1,2\rangle
\mathbf r_v=\langle1,-1,1\rangle
\mathbf r_u\times\mathbf r_v=\langle3,1,-2\rangle
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=\displaystyle\sqrt{14}\int_{u=0}^{u=3}\int_{v=0}^{v=2}((u+v)+(u-v)+(1+2u+v))\,\mathrm dv\,\mathrm du
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=48\sqrt{14}
4 0
4 years ago
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