FIND THE OF P LEAVE YOUR ANSWER IN TERMS OF PU

A car has 15 gallons of gas in its tank. The car travels 35 miles per gallon of gas. It uses 1/35 of a gallon of gas to go one m

ikadub [295]

Answer:

2.86 gallons

Step-by-step explanation:

If 1/35 gallon of gas = 1 mile

To travel 100 miles,

1/35 × 100

= 0.0286 × 100

= 2.86 gallons

Therefore, the car needs 2.86 gallons of gas to travel 100 miles.

4 0

2 years ago

Bus a nut aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

kap26 [50]

Answer:

yep that hurts if u a guy

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

You and your friend are selling magazine subscriptions. You sell 8 fewer magazine subscriptions than your friend. Together you s

Xelga [282]

Answer:

b. you sold 17

c. your friend sold 25

Step-by-step explanation:

you=y your friend=x

y=x-8

42=x +y

42=x+(x-8)

42=x+x-8

42=2x-8

50=2x

25=x

Use x to solve for y...

y=25-8

y=17

3 0

3 years ago

Will Mark Brainiest!!! Simplify the following:

xz_007 [3.2K]

Answer:

1.B

2.A

3. B

Step-by-step explanation:

1. $\frac{x+5}{x^{2} + 6x +5 }$

We have the denominator of the fraction as following:

$x^{2} + 6x + 5 \\= x^{2} + (1 + 5)x + 5\\= x*x + 1x + 5x + 5*1\\= x ( x + 1) + 5(x + 1)\\= (x + 1) (x + 5)$

As the initial one is a fraction, so that its denominator has to be different from 0.

=> ( $x^{2} +6x+5$ ) ≠ 0

⇔ (x +1) (x +5) ≠ 0

⇔ (x + 1) ≠ 0; (x +5) ≠ 0

⇔ x ≠ -1; x ≠ -5

Replace it into the initial equation, we have:

$\frac{x+5}{x^{2} + 6x +5 } = \frac{x+5}{(x+1)(x+5)}$

As (x+5) ≠ 0; we divide both numerator and denominator of the fraction by (x +5)

=> $\frac{x+5}{x^{2} + 6x +5 } = \frac{x+5}{(x+1)(x+5)} = \frac{1}{x+1}$

So that $\frac{x+5}{x^{2} + 6x +5 } = \frac{1}{x+1}$ with x ≠ 1; x ≠ -5

So that the answer is B.

2. $\frac{(\frac{x^{2} -16 }{x-1} )}{x+4}$

As the initial one is a fraction, so that its denominator has to be different from 0

=> x + 4 ≠ 0

=> x ≠ -4

As $\frac{x^{2}-16 }{x-1}$ is also a fraction, so that its denominator (x-1) has to be different from 0

=> x - 1 ≠ 0

=> x ≠ 1

We have an equation: $x^{2} - y^{2} = (x - y ) (x+y)$

=> $x^{2} - 16 = x^{2} - 4^{2} = (x -4) (x +4)$

Replace it into the initial equation, we have:

$\frac{(\frac{x^{2} -16 }{x-1} )}{x+4} \\= \frac{x^{2} -16 }{x-1} . \frac{1}{x + 4}\\= \frac{(x-4)(x+4)}{x-1}. \frac{1}{x + 4}$

As (x + 4) ≠ 0 (proven above), we can divide both numerator and the denominator of the fraction by (x +4)

=> $\frac{(x-4)(x+4)}{x-1} .\frac{1}{x+4} =\frac{x-4}{x-1}$

So that the initial equation is equal to $\frac{x-4}{x-1}$ with x ≠-4; x ≠1

=> So that the correct answer is A

3. $\frac{x}{4x + x^{2} }$

As the initial one is a fraction, so that its denominator (4x + x^2) has to be different from 0

We have:

(4x + x^2) = 4x + x.x = x ( x + 4)

So that: (4x + x^2) ≠ 0 ⇔ x ( x + 4 ) ≠ 0

⇔ $\left \{ {{x\neq 0} \atop {(x+4)\neq0 }} \right.$ ⇔ $\left \{ {{x\neq 0} \atop {x \neq -4 }} \right.$

As (4x + x^2) = x ( x + 4) , we replace this into the initial fraction and have:

$\frac{x}{4x + x^{2} } = \frac{x}{x(x+4)}$

As x ≠ 0, we can divide both numerator and denominator of the fraction by x and have:

$\frac{x}{x(x+4)} =\frac{x/x}{x(x+4)/x} = \frac{1}{x+4}$

So that $\frac{x}{4x+x^{2} } = \frac{1}{x+4}$ with x ≠ 0; x ≠ -4

=> The correct answer is B

3 0

3 years ago

Several different bus routes stop at the corner of Second St. and Lincoln Ave. A Wilkenson bus arrives every 21 minutes and a Ha

Olin [163]

Answer:

Both buses will arrive at the stop at 6:52 AM

Step-by-step explanation:

Wilkenson Bus = Arrives every 21 minutes

Harris Road Bus = Arrives every 15 minutes

Let's find the Least Common Multiple (LCM) of 21 and 15. LCM is found, listing the prime factors of each numbers and then multiplying each factor the greatest number of times it occurs in either numbers:

LCM 21 = 3 × 7

LCM 15 = 3 × 5

LCM (21 , 15) = 3 × 7 × 5 = 105

In 105 minutes both buses will arrive at the same time again

105 minutes = 1 h 45 min

5:07 AM + 1h 45 min = 6:52 AM

3 0

3 years ago