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3 years ago

How do I solve the equation solving x would I equal them to each other?

Mathematics

2 answers:

anzhelika [568]3 years ago

8 0

Since they are both degrees of an angle they would be equal:

3x+80 = 7x-40

80 = 4x-40

120 = 4x

x = 120/4 = 30 degrees

lyudmila [28]3 years ago

4 0

7x-40 represents the central angle, the arc 3x+80 equals the central angle, it is the same, so 7x-40=3x+80. 7x-3x=80+40. 4x=120. X=30. Let’s plug it in. This can be a way to check the answer. We get: angle=170 and arc=170. So x=30 is correct.

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True or false a function can not have a repeat values in the range

SVETLANKA909090 [29]

Answer:

False. false false false false

5 0

3 years ago

Swimming speed of salmon. The graph is showed below shows the influence of the temperature T on the maximum sustainable swimming

Doss [256]

Answer:

Here we have the relation between the speed of the salmon and the temperature.

a) the relation dS/dT tell us how the speed of the salmon changes as the temperature changes, and the units should be (if speed is m/s and temperature is in °C )

[dS/dT ] = [m/s*°C ].

b) I can not do a draw of the figure, but i can give a aproximation.

For T = 18°C, we can see that we are around the maximum of the curve, this means that around this point we will find the zero in the first derivate.

then S'(18) ≈ 0 m/s*°C

this means that around this point the changes are small.

for T = 10°C

Around this region, we can see almost a linear behavior.

so we can take a range of +-2°C

S(12°C) = 25m/s

S(8°C) = 20m/s

then the slope can be obtained using the relation:

S = (Y2 - Y1)/(X2 - X1) where this is the slope for the line that goes trough the pairs. (X1, Y1) and (X2, Y2)

S = (25 - 20)/(12 - 8) = 5/4

then we have that S´(10°C) ≈ 5/4 m/s*°C

Those two results are approximations, you may find better approximations by doing this with a ruler and drawing the tangents.

5 0

3 years ago

The attention span of children (ages 3 to 5) is claimed to be Normally distributed with a mean of 15 minutes and a standard devi

Agata [3.3K]

Answer:

If the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 15 minutes

Sample size, n = 10

Alpha, α = 0.05

Population standard deviation, σ = 4 minutes

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 15\text{ minutes}\\H_A: \mu > 15\text{ minutes}$

Since the population standard deviation is given, we use one-tailed z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Now, $z_{critical} \text{ at 0.05 level of significance for one tail} = 1.64$

Thus, we would reject the null hypothesis if the z-statistic is greater than this critical value.

Thus, we can write:

$z_{stat} = \displaystyle\frac{\bar{x} - 15}{\frac{4}{\sqrt{10}} } > 1.64\\\\\bar{x} - 15>1.64\times \frac{4}{\sqrt{10}}\\\bar{x} - 15>2.07\\\bar{x} > 15+2.07\\\bar{x} > 17.07$

Thus, the decision rule would be if the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

6 0

3 years ago

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Answer:

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3 years ago

Write xy^2-by^2-ax+ab+y^2-a as a product

Eddi Din [679]

Answer: (y^2-a)(1+x-b)

Step-by-step explanation:

Factor out the common terms: =x(y^2-a)-by^2+ab+y^2-a

Then rewrite as: =(y^2-a)x-by^2+ab+1 x (y^2-a)

Factor out the common term (y^2 - a): =(y^2-a)(x+1)-by^2+ab

Factor out the common term b: =(y^2-a)(1+x)+b(-y^2+a)

Rewrite as: =(y^2-a)(1+x)-(y^2-a)b

Factor out the common term (y^2 - a): =(y^2-a)(1+x-b)

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3 years ago