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Naddik [55]
3 years ago
14

Multiplying binomials determine the product. (10-3) (10-8)

Mathematics
2 answers:
oksano4ka [1.4K]3 years ago
8 0
PEMDAS works for this equation. 10-3=7 10-8=2
7x2=14
borishaifa [10]3 years ago
7 0

Answer:

The Product is 14.

Step-by-step explanation:

If you type the problem in math wa y calculator it should help you.

you can also you desmos calculator(s)

If you need anything else just ask me.

Hope this helps.

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C. Find the sqr root of 20 and get. about 4.47
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If the altitude of an isosceles right triangle has a length of x units, what is the length of one leg of the large right triangl
zheka24 [161]

To solve the problem we must know about isosceles right triangle and the Pythagorean Theorem.

<h2>Isosceles Triangle</h2>

A triangle with two sides of equal length and the corresponding angles of equal measurement is known as Isosceles Triangle.

<h2>Right Triangle</h2>

A tringle with a 90° angle is known as a right-angled triangle.

The length of one leg of the large right triangle in terms of x is x√2.

<h2>Explanation</h2>

Given to us

  • If the altitude of an isosceles right triangle has a length of x units,

<h3>In ΔABC,</h3>

As it is given to us that the triangle is a right angle triangle the two sides of the triangle will be equal to each other.

therefore, AB = BC

Also, given that the altitude of the triangle is equal to x. therefore,

AB = x

AB = BC = x,

<h3>What is the largest side of the right triangle?</h3>

We know that in a right-angled triangle the longest side of the triangle is the hypotenuse, which is always opposite to the 90° angle.

<h3>In ΔABC,</h3>

AC is the hypotenuse,

Using Pythagoras theorem,

AC² = AB² + BC²

AC^2 = {x^2 + x^2}\\\\&#10;AC = \sqrt{x^2 + x^2}\\\\&#10;AC = \sqrt{2x^2 }\\\\&#10;AC = x\sqrt{2 }\\

thus, the value of hypotenuse is x√2.

Hence, the length of one leg of the large right triangle in terms of x is x√2.

Learn more about Hypotenuse:

brainly.com/question/8587612

6 0
2 years ago
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Please Help
patriot [66]
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6 0
3 years ago
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Please help fast it’s a test
photoshop1234 [79]

Answer:

The first box is 8 and the second box is 96

Step-by-step explanation:

Hope this helps!

4 0
3 years ago
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What is the distance between (-7, -2) and (13,-23)
Zolol [24]

Step-by-step explanation:

here,

x1=-7

x2=13

y1=-2

y2=-23

so

\boxed{\blue{ distance=\sqrt{(y2-y1)^2+(x2-x2)^2} }} ⠀

<em>=</em>\tt{\sqrt{(-23-(-2))^2+(13-(-7))^2}} ⠀

=\tt{\sqrt{(-21)^2+(20)^2}  } ⠀

=\tt{\sqrt{ 441+400} } ⠀

=\tt{\sqrt{841}  } ⠀

=\tt{ 29 } ⠀

So,

the distance between (-7, -2) and (13,-23)=29

6 0
3 years ago
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