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3 years ago

Given the equation 2^2-^1=8^x-1 what is the value of x

Mathematics

1 answer:

Lady bird [3.3K]3 years ago

5 0

Answer:

i can't solve it because it's not complete

you need something 2^2 (right here) -^1=8^x-1

Step-by-step explanation:

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Is this correspondence a function?

Afina-wow [57]

I’m not sure, sorry if I’m wrong but I’d say yes .

Explanation: A function is a correspondence between two sets where each element in the first set, called the domain, corresponds to exactly one element in the second set, called the range.
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3 years ago

-5x^5+35x^4-30x^3 can someone help me pls

vampirchik [111]

Answer:

if im correct -5^3

Step-by-step explanation:

7 0

3 years ago

Suppose a figure is located in Quadrant I. Which of the following sequences will result in an image that is located in Quadrant

lesantik [10]

Answer:

So option b is right.

Step-by-step explanation:

Given that a figure is located in Quadrant I.

The figure is transformed and the image is located in quadrant iv.

We have to select the option which would have resulted in this.

A) rotating 360 degrees would result in the same place i.e. I quadrant hence wrong.

B) rotating 180 degrees counterclockwise, will make y coordinate negative but x coordinate will remain as it is.

Hence we get image in the IV quadrant.

THis option is correct

C) Rotating90 degrees counterclockwise will not transform all the coordinates to the IV quadrant hence wrong

D) Rotating 270 degrees counterclockwise would make the image in III quadrant hence wrong

So option b is right.

5 0

3 years ago

SOMEONE PLEASE HELP! IM REALLY CONFUSED

Mamont248 [21]

Answer:

thanks

Step-by-step explanation:

3 0

3 years ago

Write an equation in slope-intercept form for the line that passes through the point ( -1 , -2 ) and is perpendicular to the l

mamaluj [8]

The equation in slope-intercept form for the line that passes through the point ( -1 , -2 ) and is perpendicular to the line − 4 x − 3 y = − 5 is $y = \frac{3}{4}x - \frac{5}{4}$

Solution:

The slope intercept form is given as:

y = mx + c ----- eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Given that the line that passes through the point ( -1 , -2 ) and is perpendicular to the line − 4 x − 3 y = − 5

Given line is perpendicular to − 4 x − 3 y = − 5

− 4 x − 3 y = − 5

-3y = 4x - 5

3y = -4x + 5

$y = \frac{-4x}{3} + \frac{5}{3}$

On comparing the above equation with eqn 1, we get,

$m = \frac{-4}{3}$

We know that product of slope of a line and slope of line perpendicular to it is -1

$\frac{-4}{3} \times \text{ slope of line perpendicular to it}= -1\\\\\text{ slope of line perpendicular to it} = \frac{3}{4}$

Given point is (-1, -2)

Now we have to find the equation of line passing through (-1, -2) with slope $m = \frac{3}{4}$

Substitute (x, y) = (-1, -2) and m = 3/4 in eqn 1

$-2 = \frac{3}{4}(-1) + c\\\\-2 = \frac{-3}{4} + c\\\\c = - 2 + \frac{3}{4}\\\\c = \frac{-5}{4}$

$\text{ substitute } c = \frac{-5}{4} \text{ and } m = \frac{3}{4} \text{ in eqn 1}$

$y = \frac{3}{4} \times x + \frac{-5}{4}\\\\y = \frac{3}{4}x - \frac{5}{4}$

Thus the required equation of line is found

8 0

3 years ago