A
41 is not divisible by any number other than 1 and itself so it is prime and not composite and obviously 41 is a whole number so BCD are eliminated
Answer:
No
Step-by-step explanation:
Substitute the values and see.
-5 ≥ -2(-5) +4
-5 ≥ 14 . . . . . . . . FALSE
The point (-5, -5) is <em>not a solution</em> to the inequality
y ≥ -2x +4
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A graph can quickly show you this.
Answer:
29) discriminant is positive
30) discriminant is 0
31) discriminant is negative
Step-by-step explanation:
the graph of a quadratic function y=ax^2 + bx + c is shown. Tell whether the discriminant of ax^2 + bx + c = 0 is positive, negative, or zero.
In the graph of question number 29 we can see that the graph intersects the x axis at two points
so the equation has 2 solutions.
When the equation has two solution then the discriminant is positive
In the graph of question number 30 we can see that the graph intersects the x axis at only one point
so the equation has only 1 solution.
When the equation has only one solution then the discriminant is equal to 0
In the graph of question number 30 we can see that the graph does not intersects the x axis
so the equation has 2 imaginary solutions.
When the equation has two imaginary solutions then the discriminant is negative
16 cm -10 days
1 cm --- x days
x=1*10/16=5/8=0.625 days
Yes it should, 0 is still a number even though it’s value is nothing. You can’t get to -1 without 0.
