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RideAnS [48]
3 years ago
14

Please help! select all that apply

Mathematics
1 answer:
alina1380 [7]3 years ago
6 0
Answer: 2nd one and the 4th one
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Y – 1 = 2(x – 2), solve for y
solmaris [256]

Answer:

y = 2x-3

Step-by-step explanation:

y – 1 = 2(x – 2)

Distribute

y-1 =2x-4

Add 1 to each side

y-1+1 = 2x-4+1

y = 2x-3

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2/5 of 2/3
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4/15 is your answer my friend

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i think it A

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Simplify and show work <br><br> 5x - (6 - x)
Scilla [17]

Answer:

6x-6

Step-by-step explanation:

5x-(6-x)

First you distribute the negative to (6-x) which makes -6+x, then you just subtract that from 5x which makes 5x-6+x then you just simplify into 6x-6.

4 0
3 years ago
The temperature falls from 0 degrees to Negative 12 and one-fourth degrees in 3 and one-half hours. Which expression finds the c
ANEK [815]

Answer:

The expression used to find the change in temperature per hour is Algebraic expression

Thus per hour; the temperature falls at the rate of - 3\dfrac{1}{2}^0

Step-by-step explanation:

A temperature falls from 0 to  - 12\dfrac{1}{4}     in     3\dfrac{1}{2} \ hours

Which expression finds the change in temperature per hour.

From the above given information;

The initial temperature is 0

The final temperature is  - 12\dfrac{1}{4}  

The change in temperature is \Delta T = T_2  -  T_1

\Delta  T = -12\dfrac{1}{4} -0

\Delta T = -12.25

Thus;

-12.25 ° = 3.5 hours

To find the change in x°   per hour; we have;

x°            = 1 hour

The expression used to find the change in temperature per hour is Algebraic expression

From above if we cross multiply ; we have;

(- 12.25° × 1 hour) = (x° × 3.5 hour)

Divide both sides by 3.5 hours; we have:

\dfrac{-12.25^0*1 }{3.5}=\dfrac{ x^0 *3.5}{3.5}

x° =  - 3.5

x° = - 3\dfrac{1}{2}

Thus per hour; the temperature falls at the rate of - 3\dfrac{1}{2}^0

8 0
3 years ago
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