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cricket20 [7]
3 years ago
14

A store sells small pumpkins. The graph shows the cost c of p pumpkins. Write an equation that represents c.

Mathematics
2 answers:
tiny-mole [99]3 years ago
6 0

Answer:

c = 5p

Step-by-step explanation:

Since the line passes through the origin the equation is of the form

c = mp ( m is the slope )

Consider the points (0, 0 ) and (1, 5 ), then

m = \frac{rise}{run} = \frac{5}{1} = 5

The equation representing the quanties is

c = 5p

Sedaia [141]3 years ago
4 0

Answer:(5,1)

Step-by-step explanation:

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Find the slope of the line that passses thruogh 1,5 and 10,9
vichka [17]

Answer:  The slope is 4/9  or -4/-9.

Step-by-step explanation:

(1,5)  

(10,9)   Find the difference in the y values and divide it by the difference in the x values.

5-9= -4

1- 10= -9

-4/-9= 4/9

so the slope is 4/9  

Using the slope we could also find the y-intercept and write the equation.

5=4/9 (1) + b    where b is the y-intercept

  5= 4/9 + b

-4/9   -4/9

b= 41/9  

Now we will have the equation  y= 4/9 + 41/9

4 0
3 years ago
Simplify to a single power of 6:
Anestetic [448]

Answer:

6^2

Step-by-step explanation:

it is a division between two power with the same base, so we have to subtract the exponents

6^(6-4) = 6^2

5 0
3 years ago
Read 2 more answers
Cindy took her five grandchildren to the movies, where she offered to buy all of them popcorn and candy. A popcorn bag costs $4.
Svetradugi [14.3K]

Answer:

She buys 5 boxes of popcorn and 6 boxes of candy

Step-by-step explanation:

this is because 5 times 4.00 is 20$ and 2.50 times 6 is 15$

15 + 20 is 35

so your answer is 5 boxes of popcorn and 6 boxes of candy

hope this helped :D

6 0
2 years ago
Solve the system of equations below by graphing.
AleksandrR [38]
I think it would be B hope it helps
5 0
3 years ago
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Quadrilateral ABCD is located at A (−2, 2), B (−2, 4), C (2, 4), and D (2, 2). The quadrilateral is then transformed using the r
Mademuasel [1]
New cordinates are formed by adding 7 in x and subtracting 2 from y
A(−2, 2) =A ' (-2 +7 , 2 - 1 ) = A' (5,1)
B(−2, 4)  = B' (-2 + 7 , 4 -1 )= B' (5,3)
C(2, 4)   =  C' (2 + 7 , 4 -1 )= C' (9,3)
<span>D(2, 2)   D' (2 + 7 , 2 -1 ) = D' ( 9 , 1)</span><span>

</span>
8 0
2 years ago
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