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3 years ago

Rewrite the equation 8x + 6x2 - 7= in standard form and identify a, b, and c.

Mathematics

1 answer:

Andru [333]3 years ago

8 0

Answer:

a = 6

b = 8

c = -7

Step-by-step explanation:

In standard form, we have ;

y = ax^2 + bx + c

Here, we have;

6x^2 + 8x - 7

a is the coefficient of x^2 which is 6 in this case

b is the coefficient of x which is 8

c is the last number which is -7

So we have;

a = 6

b = 8

c = -7

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The sides of a triangle are in the ratio 12:17: 25 and its perimeter is 540cm. The area is:

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Find the height of the triangle using the Pythagoras theorem

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3 years ago

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The radius would be 2

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3 years ago

If tan theta = startfraction 11 over 60 endfraction, what is the value of cot theta?

Dennis_Churaev [7]

The value of $cot\theta$ when $tan\theta =\frac{11}{60}$ comes to be $\frac{60}{11}$ .

Given that trigonometric ratio:

$tan\theta = \frac{11}{60}$

<h3>What is the tangent of an angle?</h3>

The tangent of an angle is the ratio of the opposite side(to that angle) to the adjacent side(to that angle).

So, for the given problem

Opposite side to $\theta$ = 11

Adjacent side to $\theta$ = 60

So, $cot \theta =\frac{AdjacentSide }{OppositeSide}$

$cot\theta =\frac{60}{11}$

Therefore, the value of $cot\theta$ when $tan\theta =\frac{11}{60}$ comes to be $\frac{60}{11}$ .

To get more about trigonometric ratios visit:

brainly.com/question/24349828

6 0

2 years ago

On a certain day the temperature in Austin was 10.2°C and the temperature in New York City was -4.8°C. What is the difference i

Flura [38]

Answer:

15°C

Step-by-step explanation:

Find the difference by subtracting -4.8 from 10.2

10.2 - (-4.8)

Subtracting a negative number changes to adding a positive number:

10.2 + 4.8

= 15

So, the difference in temperature between the two cities is 15°C

8 0

3 years ago

According to data from a medical association, the rate of change in the number of hospital outpatient visits, in millions, in

GaryK [48]

Answer:

a) $f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000$

b) f(t=2015) = 264,034,317.7

Step-by-step explanation:

The rate of change in the number of hospital outpatient visits, in millions, is given by:

$f'(t)=0.001155t(t-1980)^{0.5}$

a) To find the function f(t) you integrate f(t):

$\int \frac{df(t)}{dt}dt=f(t)=\int [0.001155t(t-1980)^{0.5}]dt$

To solve the integral you use:

$\int udv=uv-\int vdu\\\\u=t\\\\du=dt\\\\dv=(t-1980)^{1/2}dt\\\\v=\frac{2}{3}(t-1980)^{3/2}$

Next, you replace in the integral:

$\int t(t-1980)^{1/2}=t(\frac{2}{3}(t-1980)^{3/2})- \frac{2}{3}\int(t-1980)^{3/2}dt\\\\= \frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}+C$

Then, the function f(t) is:

$f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+C'$

The value of C' is deduced by the information of the exercise. For t=0 there were 264,034,000 outpatient visits.

Hence C' = 264,034,000

The function is:

$f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000$

b) For t = 2015 you have:

$f(t=2015)=0.001155[\frac{2}{3}(2015)(2015-1980)^{1/2}-\frac{4}{15}(2015-1980)^{5/2}]+264,034,000\\\\f(t=2015)=264,034,317.7$

3 0

3 years ago