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ella [17]
3 years ago
11

Instructions: State what additional information is required in order

Mathematics
1 answer:
irga5000 [103]3 years ago
8 0

Answer:

TU ≅ CB

Step-by-step explanation:

HL Postulates that when a leg and the hypotenuse of a right triangle are congruent to a corresponding leg and hypotenuse of another, then both right triangles are congruent.

Both right triangles shown in the diagram above is indicated to possess corresponding lengths of a leg, that is side UV ≅ side BA

We need an additional information that shows that the hypotenuse, TU, of ∆TUV is congruent to the hypotenuse, CB of ∆CBA.

Therefore, additional information needed is TU ≅ CB

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The graph of the line y= 3 is a line that has which of the following characteristics?
vaieri [72.5K]

Answer:

21

Step-by-step explanation:

4 0
3 years ago
21 = m + 9 m = 11 is it a solution
Zarrin [17]
No because 21=(11)+9
21 can’t equal to 20
7 0
4 years ago
1. (15 + 70 – 5^2) ) divide (36 – 6)<br><br> 2. (11 + 22 – 3) divide 3 - 32
Julli [10]

1) 15 + 70 - 25/36-6

  85 - 25/30

= 60/30

=2

2) 11 + 22 - 3/3-32

=30/-29

=- 30/29

8 0
3 years ago
Read 2 more answers
La rueda delantera de una moto mide 50cm de diámetro. ¿Qué distancia ha recorrido la moto si la rueda ha dado 120 vueltas? ¿Cuán
son4ous [18]

Answer:2.8333333

Step-by-step explanation:

8 0
3 years ago
Part A
Nitella [24]

Answer:

P = 300

r = 0.15

n = 12

A(t) = 300(1.0125)^12t

Step-by-step explanation:

Given that:

Total credit taken for book purchase = $300

Annual Interest rate = 15% compounded monthly

Time or period = 4 years

P(1 + r/n)^nt

P in the expression above means the principal amount which is the total credit spent on book purchase = $300

r = annual interest rate on Emma's account = 15% = 15/100 = 0.15

n = number of compounding times per period ; loan which compounds monthly = number of months in a year = 12

Hence,

P = $300 ; r = 0.15 ; n = 12

Substituting into the equation :

P(1 + r/n)^nt

Simplified expression written in terms of t:

Final amount, A after t years

A(t) = 300(1 + 0.15/12)^12t

A(t) = 300(1 + 0.0125)^12t

A(t) = 300(1.0125)^12t

3 0
3 years ago
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