Answer:
1. 15x^7y^2 + 4x^3 => x^3(15x^4y^2 + 4)
2. 15x^7y^2 + 3x => 3x(5x^6y^2 + 1)
3. 15x^7y^2 + 6xy => 3xy(5x^6y + 2)
4. 15x^7 + 10y^2 => 5(3x^7 + 2y^2)
Step-by-step explanation:
To obtain the answer to the question, first let us factorise each expression. This is illustrated below:
1. 15x^7y^2 + 4x^3
Common factor is x^3, therefore the expression is written as:
x^3(15x^4y^2 + 4)
2. 15x^7y^2 + 3x
Common factor is 3x, therefore the expression is written as:
3x(5x^6y^2 + 1)
3. 15x^7y^2 + 6xy
Common factor is 3xy, therefore the expression is written as:
3xy(5x^6y + 2)
4. 15x^7 + 10y^2
Common factor is 5, therefore the expression can be written as:
5(3x^7 + 2y^2)
V = LWH
<span>V = 50 * 1 * 1</span>
Answer:
12 m
Step-by-step explanation:
Given that the design, ABCD, was dilated to get a photocopy, EFGH, a scale factor or ratio was multiplied by the original lengths of the design to get the new measurement of the photocopy.
Thus, we are given the ratio, CD:GH = 2:3.
This means, any of the corresponding lengths of both figures would be in that same ratio.
Using the ratio of the design to the photocopy, 2:3, we can find the length of side EH of the photocopy.
The corresponding side of EH in the design is AD = 8m. Thus, AD to EH = ⅔
Cross multiply
Divide both sides by 2 to make EH the subject of formula
The length of side EH = 12 m
Answer:
107 more girls will do gym on Saturday than Thursday and Friday altogether
Step-by-step explanation:
300 girls will do gym on Saturday.
100 girls did gym on Thursday
and 93 girls did gym on Friday.
now,
300 - (100 + 93)
300 - 193 = 107
