Write a program that will add up the series of numbers: 99, 98, 97… 3, 2, 1. The program should print the running total as well
1 answer:
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Answer:
p(x,n)
1. if(n==0) [if power is 0]
2. then result =1.
3.else
4. { result=1.
5. for i=1 to n.
6. { result = result * x. } [each time we multiply x once]
7. return result.
8. }
Let's count p(3,3)
30, so come to else part.
i=1: result = result *3 = 3
i=2: result = result *3 = 9
i=2: result = result *3 = 27
Explanation:
here the for loop at step 4 takes O(n) time and other steps take constant time. So overall time complexity = O(n)
Answer:
The correct loop is as follows:
for year in range(starting_tuitionYear, ending_tuitionYear, increment):
tuition = startingTuition + rate * startingTuition
startingTuition = tuition
print('Tuition for the year of ' + str(year)+ ' is ' + str(tuition));
Explanation:
Required
The correction to the attached program
Some variables are not needed; so, I've removed the redundant variables.
The main error in the program is in the loop;
After the tuition for each year has been calculated, the startTuition of the next year must be set to the current tuition
<em>See attachment for complete program</em>
