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amid [387]
2 years ago
5

In which of the following situations would it be most appropriate to choose lossy compression over lossless compression?

Computers and Technology
1 answer:
malfutka [58]2 years ago
7 0

Storing music files on a smartphone in order to maximize the number of

songs that can be stored is most appropriate for choosing lossy

compression over lossless compression.

<h3>What is Lossy compression?</h3>

Lossy compression refers to a type of data compression which results in

the file size being small. Most times the quality is reduced as a result of

this .

This gives rise to more space being made available for the storage of more

song files which is why it is most appropriate.

Read more about Lossy compression here brainly.com/question/18806025

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Write a C++ program to count even and odd numbers in array. The array size is 50. The array elements will be entered by the user
vlabodo [156]

Answer:

The program in C++ is as follows:

#include <iostream>

using namespace std;

int main(){

   int numbers[50];

   int evekount = 0, odkount = 0;

   for(int i = 0; i<50;i++){

       cin>>numbers[i];

       if(numbers[i]%2==0){            evekount++;        }

       else{            odkount++;        }

   }

   cout<<"Even Count: "<<evekount<<endl;

   cout<<"Odd Count: "<<odkount<<endl;

   return 0;

}

Explanation:

This declares the integer array of number

   int numbers[50];

This initializes the even count and odd count to 0

   int evekount = 0, odkount = 0;

This iterates from 1 to 50

   for(int i = 0; i<50;i++){

This gets input for the array

       cin>>numbers[i];

This checks for even

<em>        if(numbers[i]%2==0){            evekount++;        }</em>

This checks for odd

<em>        else{            odkount++;        }</em>

   }

This prints the even count

   cout<<"Even Count: "<<evekount<<endl;

This prints the odd count

   cout<<"Odd Count: "<<odkount<<endl;

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Answer:

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Harlamova29_29 [7]

Answer:

Explanation:

Hello friend !!!!!!!!!!!!

The answer is <u><em>school zone</em></u>

Hope this helps

plz mark as brainliest!!!!!!!

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Answer:

A. true

Explanation:

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