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4 years ago

Solve for x. Please show answer step by step. Thanks

Mathematics

2 answers:

Bad White [126]4 years ago

6 0

X has X X hasX has to equal

elena-s [515]4 years ago

3 0

X=4. Because 5+3=8. and both lines are equal. so X has to equal 4.

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What the number is 1/10 the value of 237

Troyanec [42]

1/10 the value of 237 means we must multiply 1/10 by 237

1/10 * 237 = 23.7

Hope this helps!

4 0

3 years ago

Which of the following expressions is equivalent to

ivanzaharov [21]

$\frac{1}{2}y^2 (6x + 2y+12x-2y)\\\\= \frac{1}{2}y^2 (18x)\\\\=9xy^2$

<span>A) 9xy²</span>

3 0

3 years ago

Read 2 more answers

How many times larger than 2x10^3 is 6x10^6?

Zielflug [23.3K]

Answer: 5,998,000

Step-by-step explanation:

2x10^3= 2,000

6x10^6= 6,000,000

In translation, Use 1 x The Initial SIG FIGS, or first numbers. 10x10 is 100, and notice how 10 and 10 have 2 zeros, so 1x1 = 1 +00 is a way to construct the number.

In this case, the 10^x, the x can represent the number of zeros after our first value.

So, 6 + six zeros, or 6,000,000

and, 2 + 3 zeros, or 2,000

To find the difference, subtract the numbers from eachother and extract the absolute value, (meaning the final answer won't be negative).

So, 6,000,000 - 2,000 = 5,998,000, which is the answer to the prompt!

Hope this Helped!

3 0

3 years ago

I NEED HELP!!!!

sp2606 [1]

Answer:

About 50% percent

Step-by-step explanation:

20 is 50 percent of 40, so 21 is about 50 percent (52.5 %)

~theLocoCoco

3 0

3 years ago

Read 2 more answers

A couple plans to have children until they get a girl, but they agree they will not have more than three children, even if all

Alex_Xolod [135]

Answer:

$E(X) = 1*0.52+ 2*0.25 +3*0.23= 1.71$

Now we can calculate the second moment with the following formula:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) = 1^2*0.52+ 2^2*0.25 +3^2*0.23= 3.59$

And the variance is given by:

$Var(X) = E(X^2) -E(X)$

And replacing we got:

$Var(X) = 3.59 -[1.71]^2 = 0.6659$

And the standard deviation is just the square root of the variance:

$Sd(X) = \sqrt{0.6659}= 0.816$

Step-by-step explanation:

Previous concepts

For this case we define the random variable X =" how many children the couple will have" and we know the following distribution:

X 1 2 3

P(X) 0.52 0.250 0.230

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

Solution to the problem

For this case we can find the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(X) = 1*0.52+ 2*0.25 +3*0.23= 1.71$

Now we can calculate the second moment with the following formula:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) = 1^2*0.52+ 2^2*0.25 +3^2*0.23= 3.59$

And the variance is given by:

$Var(X) = E(X^2) -E(X)$

And replacing we got:

$Var(X) = 3.59 -[1.71]^2 = 0.6659$

And the standard deviation is just the square root of the variance:

$Sd(X) = \sqrt{0.6659}= 0.816$

4 0

3 years ago