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Tamiku [17]
3 years ago
9

3. Which shows three ratios equivalent to 8:20? A. 2:5, 4:10, 6:15 B. 2:5. 10:4, 6:15 C. 5:2. 4:10. 156 D. 5:2. 10:4. 15:6​

Mathematics
1 answer:
Mariulka [41]3 years ago
5 0

Answer:

The answer is B.

2:5

10:4

6:15

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(2x-20) + 86 what is the the value of x
julsineya [31]
When (2x-20)+86=0
2x-20=-86
2x=-46
x=-23
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3 years ago
If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be
babymother [125]

Answer:

If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.

Step-by-step explanation:

Here in this question, we want to state what will happen if the null hypothesis is true in a chi-square test.

If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.

This is because at a higher level of discrepancies, there will be a strong evidence against the null. This means that it will be rare to find discrepancies if null was true.

In the question however, since the null is true, the discrepancies we will be expecting will thus be small and common.

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3 years ago
Help me and ill mark you brainliest
Harman [31]

Answer:

question 13 = D

Step-by-step explanation:

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6 0
2 years ago
The product of a number and nine is added to five. The result is thirty-
Nuetrik [128]

Answer:

The number is 11

Step-by-step explanation:

6x+38=9x+5

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x= 11

5 0
3 years ago
The children in my subdivision were bored one summer and decided to hold a competition to see who could run to the end of the st
Ainat [17]

Answer:

6.7% of children who finished the race in under 45 seconds.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 75 seconds

Standard Deviation, σ =  20 seconds

We are given that the distribution of time of completion is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(finished the race in under 45 seconds.)

P(x < 45)

P( x < 45) = P( z < \displaystyle\frac{45 - 75}{20}) = P(z < -1.5)

Calculation the value from standard normal z table, we have,  

P(x < 45) = 0.067 = 6.7\%

6.7% of children who finished the race in under 45 seconds.

4 0
3 years ago
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