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3 years ago

What about 11 movie tickets

Mathematics

1 answer:

anygoal [31]3 years ago

3 0

Answer:

Step-by-step explanation:

yes please

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Plot on a number line 4/7

Serjik [45]

Answer:

It will be over 4 and up 7. 4 spaces on the x axis, and 7 spaces on the y axis, the y axis is vertical. Think that the y has a v in it which stands for vertical

Step-by-step explanation:

5 0

3 years ago

A baseball is hit so that the height above the ground is given by the equation h=-16t^2+96t+3, where h is the height in feet and

Alexus [3.1K]

H'=-32t+96
0=-32t+96
-96=-32t
3=t

3 seconds

H=-16t^2+96t+3
H=48^2+288+3

H=48^2+291

6 0

3 years ago

The number of hours spent per week on household chores by all adults has a mean of 28 hours and a standard deviation of 7 hours.

Alchen [17]

Answer:

Probability that the mean hours spent per week on household chores by a sample of 49 adults will be more than 26.75 is 0.89435.

Step-by-step explanation:

We are given that the number of hours spent per week on household chores by all adults has a mean of 28 hours and a standard deviation of 7 hours.

Also, sample of 49 adults is given.

Let X = number of hours spent per week on household chores

So, assuming data follows normal distribution; X ~ N( $\mu=28,\sigma^{2}=7^{2}$ )

The z score probability distribution for sample mean is given by;

Z = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = mean hours = 28

$\sigma$ = standard deviation = 7 hours

n = sample of adults = 49

Let $\bar X$ = sample mean hours spent per week on household chores

So, probability that the mean hours spent per week on household chores by a sample of 49 adults will be more than 26.75 is given by =P( $\bar X$ > 26.75 hours)

P( $\bar X$ > 26.75 hours) = P( $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ > $\frac{26.75-28}{\frac{7}{\sqrt{49} } }$ ) = P(Z > -1.25) = P(Z < 1.25)

= 0.89435 {using z table}

Therefore, probability that the mean hours spent per week on household chores is more than 26.75 is 0.89435.

4 0

3 years ago

Read 2 more answers

One variable examined is the survival rate 10 years after tagging. The scientists observed that 10 of the 50 metal tagged pengui

Oksana_A [137]

Answer: 90% confidence interval would be $(-0.2483,-0.0717)$

Step-by-step explanation:

Since we have given that

n₁ = 50

Number of metal tagged penguins survived = 10

So, $p_m=\dfrac{10}{50}=0.2$

n₂ = 50

Number of electronic tagged penguins = 18

So, $p_e=\dfrac{18}{50}=0.36$

So, at 90% confidence interval, z = 1.28

So, interval would be

$(p_m-p_e)\pm z\sqrt{\dfrac{p_m(1-p_m)}{n}+\dfrac{p_e(1-p_e)}{n}}\\\\=(0.2-0.36)\pm 1.28\sqrt{\dfrac{0.2\times 0.8}{50}+\dfrac{0.36\times 0.64}{50}}\\\\=-0.16\pm 0.0883\\\\=(-0.16-0.0883,-0.16+0.0883)\\\\=(-0.2483,-0.0717)$

Hence, 90% confidence interval would be

$(-0.2483,-0.0717)$

6 0

3 years ago

For which equation would n = 0 not be a solution?

4vir4ik [10]

For the first equation n + 4 = 5, because 0 + 4 is not equal 5

5 0

3 years ago