First and last terms of the given equation are perfect squares. They can be written as
(4p^2)^2+ 2.(4p^2).5+(5)^2
It's like identity 1: (a+b)^2=a^2+2ab+b^2
So a=4p^2 and b=5
Therefore it is equal to (4p^2+5)^2
Answer:
None of the Above
Step-by-step explanation:
Hope this helps
Answer: option C) 343
Justification:
The sequence of the denominators is:
term denominator
1 1 = 1^3
2 8 = 2^3
3 27 = 3^3
4 64 = 4^3
5 5^3 = 125
6 6^3 = 216
7 7^3 = 343
And that is the term searched. So, the answer is the option C) 343.
Answer:
36,220
Step-by-step explanation:
id.k
Answer:
Step-by-step explanation:6+30m
6=-30m
Divide through by 30
6/30=-30/-30m
M=-1/5