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solniwko [45]
3 years ago
7

uestion 4 of 10structions: Select the correct answer from the drop down menu.(xy)nsider the expressione equivalent simplified fo

rm of this expression isx 3/9/(xn-7)ext Reset

Mathematics
2 answers:
nata0808 [166]3 years ago
7 0
\dfrac{(xy)^{-2}}{(3y)^2x^{-5}}=\dfrac{x^{-2}y^{-2}}{9y^2x^{-5}}=\dfrac{x^3}{9y^4}
nadya68 [22]3 years ago
3 0

Answer:

\frac{x^{3} }{9y^{4} }

Step-by-step explanation:

The given expression is

\frac{(xy)^{-2} }{(3y)^{2} x^{-5} }

First, we use the property: (xy)^{2} =x^{2} y^{2}

\frac{(xy)^{-2} }{(3y)^{2} x^{-5} }=\frac{x^{-2} y^{-2} }{9y^{2} x^{-5} }

Then, we use the property: \frac{x^{m} }{x^{n} }=x^{m-n}

\frac{x^{-2} y^{-2} }{9y^{2} x^{-5} }=\frac{x^{-2+5} y^{-2-2} }{9} =\frac{x^{3}y^{-4}  }{9}

Next, we use the property: x^{-n} =\frac{1}{x^{-n} }

\frac{x^{3}y^{-4}  }{9}=\frac{x^{3} }{9y^{4} }

Therefore, the answer is

\frac{x^{3} }{9y^{4} }

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